Submission #1350581

#TimeUsernameProblemLanguageResultExecution timeMemory
1350581FIFI_cppTycho (BOI23_tycho)C++20
12 / 100
0 ms1092 KiB
#include <bits/stdc++.h>
#include <iostream>
#include <vector>
#include <algorithm>
#include <numeric>
#include <cstdlib>
#include <cmath>
#include <queue>
#include <stack>
#include <deque>
#include <fstream>
#include <iterator>
#include <set>
#include <map>
#include <unordered_map>
#include <iomanip>
#include <cctype>
#include <string>
#include <cassert>
#include <set>
#include <bitset>
#include <unordered_set>
#include <numeric>

#define all(a) a.begin(), a.end()
#define fast ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
#define pb push_back
#define ppi pair<int,pair<int,int>>
#define int int64_t

using namespace std;
//    /\_/\
//   (= ._.)
//   / >  \>
// encouraging cat
const int INF = 10000000000000000;
//const int mod = 1000000007;
const int mod = 998244353;
const int MAXN = 1005;
const int MAXP = 103;
//ifstream fin('xor.in');
//ofstream fout('xor.out');
int dp[MAXN][MAXP];
signed main()
{
    int fin, period, dmg, n;
    cin >> fin >> period >> dmg >> n;
    vector<int> pos(n, 0);
    for (int i = 0;i < n;i++)
    {
        cin >> pos[i];
    }
    pos.pb(fin);
    n++;
    for (int i = 0;i < n;i++)
    {
        for (int j = 0;j < period;j++)
        {
            dp[i][j] = INF;
        }
    }
    dp[0][pos[0] % period] = ((pos[0] - 1) / period) * dmg + pos[0];
    for (int i = 0;i < n - 1;i++)
    {
        for (int j = 0;j < period;j++)
        {
            int cr = dp[i][j];
            int dist = pos[i + 1] - pos[i];
            int stop = period - j; // time we wait at base if we want to stop
            dp[i + 1][dist % period] = min(cr + ((dist - 1) / period) * dmg + (dist + stop), dp[i + 1][dist % period]);
            int rem = (j + dist) % period;
            dp[i + 1][rem] = min(dp[i + 1][rem], cr + ((j + dist - 1) / period) * dmg + dist);
        }
    }
    int res = INF;
    for (int j = 0;j < period;j++)
    {
        res = min(res, dp[n - 1][j]);
    }
    cout << res << '\n';
    return 0;
}
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