제출 #134999

#제출 시각아이디문제언어결과실행 시간메모리
134999lycPotemkin cycle (CEOI15_indcyc)C++14
100 / 100
392 ms91960 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; typedef pair<int, int> ii; typedef pair<int, ii> iii; typedef pair<ii, int> ri3; #define mp make_pair #define pb push_back #define fi first #define sc second #define SZ(x) (int)(x).size() #define ALL(x) begin(x), end(x) #define REP(i, n) for (int i = 0; i < n; ++i) #define FOR(i, a, b) for (int i = a; i <= b; ++i) #define RFOR(i, a, b) for (int i = a; i >= b; --i) const int MAXN = 1e3+5; const int MAXR = 1e5+5; const int MAXE = 2*MAXR; int N, R; vector<int> al[MAXN]; bool conn[MAXN][MAXN]; vector<int> g[MAXE]; int E, from[MAXE], to[MAXE], vis[MAXE], pa[MAXE]; void bfs(int s) { queue<int> q; FOR(i,0,E-1) pa[i] = -1; q.push(s); //cout << "S " << from[s] << " " << to[s] << endl; while (!q.empty()) { int u = q.front(); q.pop(); //cout << "U " << from[u] << " " << to[u] << endl; for (int v : g[u]) { //cout << "\t\tV " << from[v] << " " << to[v] << endl; if (v == s) { //cout << "ANS" << '\n'; //vector<int> edges; //for (int e = u; e != -1; e = pa[e]) edges.push_back(e); //for (auto& e : edges) { cout << from[e] << " " << to[e] << " :: "; } cout << endl; for (int e = u; e != -1; e = pa[e]) cout << to[e] << (pa[e]==-1?'\n':' '); exit(0); } else if (pa[v] == -1) pa[v] = u, q.push(v); } } } void dfs(int u) { vis[u] = 2; for (int v : g[u]) { if (vis[v] == 2) { bfs(v); // ans } else if (!vis[v]) dfs(v); } vis[u] = 1; } int main() { //freopen("in.txt", "r", stdin); ios::sync_with_stdio(false); cin.tie(0); cin >> N >> R; E = 0; FOR(i,1,R){ int A, B; cin >> A >> B; from[E] = A, to[E] = B; al[A].push_back(E++); from[E] = B, to[E] = A; al[B].push_back(E++); conn[A][B] = conn[B][A] = 1; } FOR(i,1,N) FOR(j,0,SZ(al[i])-1) { // + ^ O(E) FOR(k,j+1,SZ(al[i])-1) { // O(N) int e = al[i][j], f = al[i][k]; if (!conn[to[e]][to[f]]) g[e^1].push_back(f), g[f^1].push_back(e); } } FOR(i,0,E-1) vis[i] = 0; FOR(i,0,E-1) if (!vis[i]) dfs(i); cout << "no" << '\n'; }
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