제출 #1347237

#제출 시각아이디문제언어결과실행 시간메모리
1347237ender_shayanLiteh and Newfiteh (INOI20_litehfiteh)C++20
100 / 100
129 ms149944 KiB
#include <bits/stdc++.h>

using namespace std;


typedef long long ll;
typedef long double	ld;
typedef pair<int, int>	pii  ;
typedef pair<ll, ll>	pll  ;
typedef vector<pii>     vii  ;
typedef vector<int>     veci ;
typedef vector<pll>     vll  ;
typedef vector<ll>      vecll;

// find_by_order             order_of_key

#pragma GCC optimize("O3,unroll-loops")
//#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
#define F		        first
#define S		        second
#define pb		        push_back
#define endl            '\n'
#define Mp		        make_pair
#define all(x)          x.begin(), x.end()
#define debug(x)        cerr << #x << " = " << x << endl
#define set_dec(x)	    cout << fixed << setprecision(x);
#define fast_io         ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define file_io         freopen("in.txt" , "r" , stdin) ; freopen("out.txt" , "w" , stdout);
#define lb              lower_bound
#define ub              upper_bound
#define for1(n)         for(int i=1;i<=n;i++)
#define for0(n)         for(int i=0;i<n;i++)
#define forn(n)         for(int i=n;i>0;i--)
#define pq              priority_queue <pii, vector<pii>, greater<pii>>


const int N=1e5+4,L=19,NN=N*L;
int A[N],n,m,k,q,dp[N][L][L],mn[N][L],dpp[N];

int main(){
    fast_io
    cin>>n;
    for1(n){cin>>A[i];mn[i][0]=A[i];if(A[i]>=L)return cout<<"-1\n",0;}
    for(int j=1;j<L;j++)for1(n)if(i+(1<<j)<=n+1)mn[i][j]=min(mn[i][j-1],mn[i+(1<<(j-1))][j-1]);
    for1(n){
        for(int j=0;j<L;j++)
            dp[i][0][j]=NN;
        dp[i][0][A[i]]=0;
        if(A[i]!=0)
            dp[i][0][A[i]-1]=1;

    }
    for(short int d=1;d<L;d++){
        for1(n){
            if(i+(1<<d)>n+1)break;
            for(short int x=0;x<L;x++){
                if(mn[i][d]<x){dp[i][d][x]=NN;continue;}
                dp[i][d][x]=min(NN,min(dp[i][d-1][x]+dp[i+(1<<(d-1))][d-1][x],dp[i][d-1][x+1]+dp[i+(1<<(d-1))][d-1][x+1]+1));
            }
        }
    }
    dpp[0]=0;
    for1(n){
        dpp[i]=NN;
        for(int j=0;j<L;j++)if(i-(1<<j)>=0)
            dpp[i]=min(dpp[i],dpp[i-(1<<j)]+dp[i-(1<<j)+1][j][0]);

    }
    cout<<(dpp[n]==NN ? -1:dpp[n])<<endl;




}


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