제출 #1346787

#제출 시각아이디문제언어결과실행 시간메모리
1346787ender_shayanSemiexpress (JOI17_semiexpress)C++20
48 / 100
0 ms344 KiB
#include <bits/stdc++.h>

using namespace std;

// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/tree_policy.hpp>
// using namespace __gnu_pbds;

typedef long long ll;
typedef long double	ld;
typedef pair<int, int>	pii  ;
typedef pair<ll, ll>	pll  ;
typedef vector<pii>     vii  ;
typedef vector<int>     veci ;
typedef vector<pll>     vll  ;
typedef vector<ll>      vecll;

// find_by_order             order_of_key

//#pragma GCC optimize("O3,unroll-loops")
//#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
#define F		        first
#define S		        second
#define pb		        push_back
#define endl            '\n'
#define Mp		        make_pair
#define all(x)          x.begin(), x.end()
#define debug(x)        cerr << #x << " = " << x << endl
#define set_dec(x)	    cout << fixed << setprecision(x);
#define fast_io         ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define file_io         freopen("in.txt" , "r" , stdin) ; freopen("out.txt" , "w" , stdout);
#define lb              lower_bound
#define ub              upper_bound
#define for1(n)         for(int i=1;i<=n;i++)
#define for0(n)         for(int i=0;i<n;i++)
#define forn(n)         for(int i=n;i>0;i--)
#define pq              priority_queue <pii, vector<pii>, greater<pii>>


const ll mod = 1e9+7 ;// 998244353 ;// 1e9+9;

ll inf=1e18;
const int N=1e3+100,L=21,bs=701,NN=1e6;

ll b,c,a,t,s[N],n,m,k,ans=-1;
int main(){
    fast_io
    cin>>n>>m>>k;
    cin>>a>>b>>c;
    cin>>t;
    for1(m)cin>>s[i];
    vector<pll>vec;
    vector<ll>vec2;
    k-=m;
    s[m+1]=n+1;
    for1(m){
        if(t<0)break;
        ll l=s[i]+t/a;
        l=min(l,s[i+1]-1);
        ans+=l+1-s[i];
        ll tt=t-c*(l+1-s[i]);
        for(int j=1;j<=k;j++){
            if(tt<0)break;
            ll d=min(tt/a+1,s[i+1]-1-l);
            vec2.pb(d);
            tt-=d*c;
            l+=d;
        }
        t-=(s[i+1]-s[i])*b;
    }
    sort(all(vec2),greater<ll>());
    for0(min(k,ll(vec2.size())))ans+=vec2[i];
    cout<<ans<<endl;
    




}



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