#pragma GCC optimize("Ofast")
#pragma GCC optimize("O3,unroll-loops")
#include <bits/stdc++.h>
using namespace std;
#define f0r(i, n) for (auto i = 0; i < (n); ++i)
#define fnr(i, n, k) for (auto i = (n); i < (k); ++i)
#define all(v) (v).begin(), (v).end()
#define pb push_back
#define F first
#define S second
#define ctn(x) cout << x << '\n'
#define forl(a, l) for (auto a : l)
#define ctl(l) for (auto &a : (l)) cout << a << ' '; cout << endl;
#define lb(v, x) (lower_bound(all(v), x) - begin(v))
#define ub(v, x) (upper_bound(all(v), x) - begin(v))
#define pq priority_queue
template <class T>
using V = vector<T>;
using ll = long long;
using vi = V<int>;
using vl = V<ll>;
using pi = pair<int, int>;
using ti = tuple<int, int, int>;
using Adj = V<vi>;
using vvi = V<vi>;
#include "shoes.h"
ll solve(vi::iterator s, vi::iterator e) {
if (s == e) return 0;
int x = *s;
if (x < 0) {
auto k = s;
while (*k != -x) ++k;
swap(*k, *(s+1));
return (k - s - 1) + solve(s+2, e);
} else {
auto k = s;
while (*k != -x) ++k;
swap(*k, *(s+1));
return (k - s) + solve(s+2, e);
}
}
struct BIT {
int n;
vl bit;
BIT(int n) : n(n), bit(n + 1, 0) {}
void add(int i, ll v) {
for (++i; i <= n; i += i & -i)
bit[i] += v;
}
ll sum(int i) {
ll res = 0;
for (++i; i > 0; i -= i & -i)
res += bit[i];
return res;
}
void range_add(int l, int r, ll v) {
add(l, v);
if (r + 1 < n) add(r + 1, -v);
}
};
ll count_swaps(vi s) {
int n = s.size()/2;
if (n == 1) return s[0] > s[1];
/*
ll cnt = 0;
map<int, set<int>> mp;
f0r(i, 2*n) {
int x = s[i];
if (x < 0) {
if (mp[-x].size()) {
int y = *mp[-x].begin();
mp[-x].erase(y);
cnt += i - y;
} else mp[x].insert(i);
} else if (x > 0) {
if (mp[-x].size()) {
int y = mp[-x].front();
mp[-x].pop();
cnt += i - y - 1;
} else mp[x].push(i);
}
}
*/
map<int, queue<int>> mp;
f0r(i, 2*n) mp[s[i]].push(i);
ll cnt = 0;
//vi ad(2*n);
V<bool> dn(2*n);
BIT ad(2*n);
for (int i = 0; i < 2*n; i++) if (!dn[i]) {
int x = s[i], j = mp[-x].front();
//cout << x << ' ' << i << ' ' << j << endl;
mp[x].pop(), mp[-x].pop();
int x2 = i + ad.sum(i), j2 = j + ad.sum(j);
//cout << x2 << ' ' << j2 << endl;
cnt += x < 0 ? (j2 - x2 - 1) : (j2-x2);
ad.range_add(i, j, 1);
//for (int y = i; y <= j; ++y) ad[y]++;
dn[j] = 1;
}
return cnt;
}
