#include <bits/stdc++.h>
#define ll long long
using namespace std;
const int Nmax = 1e5 + 5, inf = 1e9 + 5;
int n, h[Nmax], w[Nmax];
int preW[Nmax], dp[Nmax];
struct line {
int a, b;
line(int A = 0, int B = 1e9) : a(A), b(B) {}
int get(int x){
return a * x + b;
}
};
struct lichao {
vector<line> st;
int n;
lichao(int N){
n = N;
st.assign(n << 2, line());
}
void add(line nw, int id, int l, int r){
int mid = (l + r) >> 1;
bool left = nw.get(l) < st[id].get(l);
bool middle = nw.get(mid) < st[id].get(mid);
if(middle) swap(nw, st[id]);
if(l == r) return;
if(left != middle) add(nw, id << 1, l, mid);
else add(nw, id << 1 | 1, mid + 1, r);
}
int query(int x, int id, int l, int r){
int res = st[id].get(x);
if(l == r) return res;
int mid = (l + r) >> 1;
if(x <= mid) return min(res, query(x, id << 1, l, mid));
else return min(res, query(x, id << 1 | 1, mid + 1, r));
}
};
// int cost(int l, int r){
// //int sum1 = preW[r - 1] - preW[l];
// //int sum2 = h[r] * h[r] + h[l] * h[l] - 2 * h[r] * h[l];
// int T = preW[r - 1] + h[r] * h[r];
// int axb = - 2 * h[r] * h[l] + h[l] * h[l] - preW[l];
// return sum1 + sum2;
// }
void solve(){
for(int i = 1; i <= n; i++){
preW[i] = preW[i - 1] + w[i];
}
lichao st(n);
st.add(line(-2 * h[1], h[1] * h[1] - preW[1]), 1, 1, n);
for(int i = 2; i <= n; i++){
int T = preW[i - 1] + h[i] * h[i];
dp[i] = st.query(h[i], 1, 1, n) + T;
st.add(line(-2 * h[i], h[i] * h[i] - preW[i] + dp[i]), 1, 1, n);
}
cout << dp[n];
}
void enter(){
cin >> n;
for(int i = 1; i <= n; i++){
cin >> h[i];
}
for(int i = 1; i <= n; i++){
cin >> w[i];
}
}
int main(){
enter();
solve();
}
