| # | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
|---|---|---|---|---|---|---|---|
| 1344908 | maximilianuggla | Feast (NOI19_feast) | Pypy 3 | 237 ms | 228688 KiB |
def maxOfKIntervalls(nums, K: int) -> int:
lowest = -10**20
intervalls1 = []
intervalls2 = []
maxEnding1 = 0
sum1 = lowest
maxEnding2 = 0
sum2 = lowest
for e in nums:
maxEnding1 = maxEnding1 + e
maxEnding2 = maxEnding2 + e
if maxEnding1 > sum1:
sum1 = maxEnding1
if maxEnding2 > sum2:
sum2 = maxEnding2
if maxEnding1 < 0:
intervalls1.append(sum1)
sum1 = lowest
maxEnding1 = 0
if maxEnding2 < sum2:
intervalls2.append(sum2)
sum2 = lowest
maxEnding2 = 0
intervalls1.append(sum1)
intervalls2.append(sum2)
intervalls1.sort(reverse=True)
intervalls2.sort(reverse=True)
res1 = 0
iterations = min(len(intervalls1), K)
for k in range(iterations):
if not intervalls1[k] < 0:
res1 = res1 + intervalls1[k]
res2 = 0
iterations = min(len(intervalls2), K)
for k in range(iterations):
if not intervalls2[k] < 0:
res2 = res2 + intervalls2[k]
return max(res2, res1)
N, I = map(int, input().split())
numbers = list(map(int, input().split()))
print(maxOfKIntervalls(numbers, I))컴파일 시 표준 출력 (stdout) 메시지
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