#pragma GCC optimize("Ofast")
#pragma GCC optimize("O3,unroll-loops")
#include <bits/stdc++.h>
using namespace std;
#define f0r(i, n) for (auto i = 0; i < (n); ++i)
#define fnr(i, n, k) for (auto i = (n); i < (k); ++i)
#define all(v) (v).begin(), (v).end()
#define pb push_back
#define F first
#define S second
#define ctn(x) cout << x << '\n'
#define forl(a, l) for (auto a : l)
#define ctl(l) for (auto &a : (l)) cout << a << ' '; cout << endl;
#define lb(v, x) (lower_bound(all(v), x) - begin(v))
#define ub(v, x) (upper_bound(all(v), x) - begin(v))
#define pq priority_queue
template <class T>
using V = vector<T>;
using ll = long long;
using vi = V<int>;
using vl = V<ll>;
using pi = pair<int, int>;
using ti = tuple<int, int, int>;
using Adj = V<vi>;
using vvi = V<vi>;
#include "mushrooms.h"
const int M = 150;
int count_mushrooms(int n) {
if (n == 2) return 1 + !use_machine({0, 1});
int c1 = use_machine({0, 1});
int c2 = use_machine({0, 2});
int cntA = 1, cntB = 0;
vi A{0}, B;
if (c1 == 0) { // 1 - A
cntA++;
A.pb(1);
} else {
cntB++;
B.pb(1);
}
if (c2 == 0) { // 2 - A
cntA++;
A.pb(2);
} else {
cntB++;
B.pb(2);
}
bool ta = 0;
vi pr;
if (cntA > cntB) {
ta = 1;
pr = {A[0], A[1]};
} else {
ta = 0;
pr = {B[0], B[1]};
}
int j = 3;
while (j < n && max(cntA, cntB) <= M) {
if (j == n-1) {
int c = use_machine({0, j});
if (c == 1) {
cntB++;
B.pb(j);
} else {
cntA++;
A.pb(j);
}
++j;
continue;
}
if (ta) {
int c = use_machine({A[0], j, A[1], j+1});
if (c & 1) {
cntB++;
B.pb(j+1);
} else {
cntA++;
A.pb(j+1);
}
if (c >= 2) {
cntB++;
B.pb(j);
} else {
cntA++;
A.pb(j);
}
} else {
int c = use_machine({B[0], j, B[1], j+1});
if (c & 1) {
cntA++;
A.pb(j+1);
} else {
cntB++;
B.pb(j+1);
}
if (c >= 2) {
cntA++;
A.pb(j);
} else {
cntB++;
B.pb(j);
}
}
j += 2;
}
if (j >= n) return cntA;
int cnt = cntA, sz = max(cntA, cntB)-1;
for (; j < n; j += sz) {
vi v;
int r = min(j+sz, n);
if (cntA > cntB) {
f0r(i, r-j) {
v.pb(A[i]);
v.pb(j+i);
}
int c = use_machine(v);
if (c & 1) {
cntB++;
B.pb(r-1);
++c;
} else {
cntA++;
A.pb(r-1);
}
cnt += r-j - c/2;
} else {
f0r(i, r-j) {
v.pb(B[i]);
v.pb(j+i);
}
int c = use_machine(v);
if (c & 1) {
cntA++;
A.pb(r-1);
++c;
} else {
cntB++;
B.pb(r-1);
}
cnt += c/2;
}
}
return cnt;
}
