Submission #1344368

#TimeUsernameProblemLanguageResultExecution timeMemory
1344368jumpBitaro’s Party (JOI18_bitaro)C++20
14 / 100
2110 ms438312 KiB
#include <bits/stdc++.h>
#define int long long
int RANGE=100000;
int n,m,q;
int height[100010];
std::set<std::pair<int,int>> dpV[100010];
std::vector<std::pair<int,int>> dpVn[100010];
int dp[100010];
int tempDp[100010];
std::vector<int> adj[100010];
std::vector<int> order;
bool visit[100010];
void dfs(int curr){
	if(visit[curr])return;
	visit[curr]=true;
	for(auto to:adj[curr]){
		dfs(to);
	}
	order.push_back(curr);
	return;
}
signed main(){
	std::cin >> n >> m >> q;
	RANGE=50;
	for(int i=0;i<m;i++){
		int s,e;
		std::cin >> s >> e;
		adj[s].push_back(e);
	}
	for(int i=1;i<=n;i++){
		dfs(i);
	}
	std::reverse(order.begin(),order.end());
	for(auto curr:order){
		dpV[curr].insert({0,curr});
		while(dpV[curr].size()>RANGE)dpV[curr].erase(dpV[curr].begin());
		for(auto to:adj[curr]){
			for(auto [value,from]:dpV[curr]){
				dpV[to].insert({value+1,from});
				while(dpV[to].size()>RANGE)dpV[to].erase(dpV[to].begin());
				//it is slightly faster
			}
			dpV[to].insert({1,curr});
			while(dpV[to].size()>RANGE)dpV[to].erase(dpV[to].begin());
			dp[to]=std::max(dp[to],dp[curr]+1);
		}
	}
	for(int i=1;i<=n;i++){
		for(auto pair:dpV[i]){
			dpVn[i].push_back(pair);
		}
		std::reverse(dpVn[i].begin(),dpVn[i].end());
	}
	while(q--){
		int t,y;
		std::vector<int> absent;
		std::cin >> t >> y;
		if(y==0){
			std::cout << dp[t] << '\n';
			continue;
		}
		for(int i=0;i<y;i++){
			int yin;
			std::cin >> yin;
			absent.push_back(yin);
		}
		int ans=-1;
		for(auto [num,from]:dpVn[t]){
			auto itr = std::lower_bound(absent.begin(),absent.end(),from);
			if(itr==absent.end()||*itr!=from){
				ans = num;
				break;
			}
		}
		if(ans!=-1){
			std::cout << ans << '\n';
			continue;
		}
		for(int i=1;i<=n;i++){
			auto itr = std::lower_bound(absent.begin(),absent.end(),i);
			if(itr==absent.end()||*itr!=i)
			tempDp[i]=0;
			else
			tempDp[i]=-1e9;
		}
		for(auto curr:order){	
			for(auto to:adj[curr]){
				tempDp[to]=std::max(tempDp[to],tempDp[curr]+1);
			}
		}
		tempDp[t]=std::max((int)(-1),tempDp[t]);
		std::cout << tempDp[t] << '\n';
	}
}
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