#include <bits/stdc++.h>
#define int long long
using namespace std;
const int inf = 1e18, N = 1e5 + 5;
struct edge {
int to, c, p;
};
map<int, vector<edge>> graph[N];
vector<int> dp(N, inf);
map<int, int> dp2[N], psum[N];
int32_t main() {
cin.tie(0)->sync_with_stdio(0);
int n, m;
cin >> n >> m;
for (int i = 1; i <= m; i++) {
int u, v, c;
int p;
cin >> u >> v >> c >> p;
graph[u][c].push_back({v, c, p});
graph[v][c].push_back({u, c, p});
psum[u][c] += p;
psum[v][c] += p;
}
dp[1] = 0;
priority_queue<tuple<int, int, int>> pq;
pq.push({0, 1, 0});
while (pq.size()) {
int cost;
int node, c;
tie(cost, node, c) = pq.top();
pq.pop();
if (c) {
if (dp2[node][c] != -cost) continue;
for (edge i : graph[node][c]) {
// We can't flip i in this case
int case1 = psum[node][c] - i.p;
if (case1 - cost < dp[i.to]) {
dp[i.to] = case1 - cost;
pq.push({-dp[i.to], i.to, 0});
}
}
} else {
if (dp[node] != -cost) continue;
for (auto &i : graph[node]) {
for (edge j : i.second) {
// Case 1: We don't flip j
int case1 = psum[node][j.c] - j.p - cost;
if (case1 < dp[j.to]) {
dp[j.to] = case1;
pq.push({-dp[j.to], j.to, 0});
}
// Case 2: We flip j but not another edge of the same colour
int case2 = j.p - cost;
if (case2 < dp[j.to]) {
dp[j.to] = case2;
pq.push({-dp[j.to], j.to, 0});
}
// Case 3: We flip j and another edge of the same colour
int case3 = -cost;
if (!dp2[j.to].count(j.c) || case3 < dp2[j.to][j.c]) {
dp2[j.to][j.c] = case3;
pq.push({-dp2[j.to][j.c], j.to, j.c});
}
}
}
}
}
cout << (dp[n] > inf ? -1 : dp[n]);
return 0;
}
