#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define all(c) (c).begin(), (c).end()
#define F first
#define S second
ll last_true(ll lo, ll hi, function<bool(ll)>ok){
lo--;
while(lo<hi){
ll mid = lo + (hi-lo+1)/2;
if (ok(mid)) lo = mid;
else hi = mid-1;
}
return lo;
}
ll first_true(ll lo, ll hi, function<bool(ll)>ok){
hi++;
while(lo<hi){
ll mid = lo + (hi-lo)/2;
if (ok(mid)) hi = mid;
else lo = mid+1;
}
return lo;
}
const ll mxN = 100;
ll grid[mxN][mxN];
bool self = false;
bool examine(ll x, ll y){
if (self) return grid[x][y];
cout << "examine " << x << " " << y << endl;
fflush(stdout);
string res; cin>>res;
return res == "true";
}
void fetch(ll n){
for (ll i=1;i<=n;i++) {
string s; cin>>s;
for (ll j=1;j<=n;j++) {
grid[i][j] = s[j-1] == '*';
}
}
}
void solve(){
ll n,x,y; cin>>n>>x>>y;
if (self) fetch(n);
ll ax=x, ay=y, bx=x, by=y;
ll d;
// while(ax > 1 && examine(ax-1, ay)) ax--;
d=1;
while(ax-d > 1 && examine(ax-d, ay)) d*=2;
ll it_ax = last_true(0, d, [&](ll j){return examine(ax-j, ay);});
ax -= it_ax;
// while(ay > 1 && examine(ax, ay-1)) ay--;
d=1;
while(ay-d > 1 && examine(ax, ay-d)) d*=2;
ll it_ay = last_true(0, d, [&](ll j){return examine(ax, ay-j);});
ay -= it_ay;
// while(bx < n && examine(bx+1, by)) bx++;
d=1;
while(bx+d < n && examine(bx+d, by)) d*=2;
ll it_bx = last_true(0, d, [&](ll j){return examine(bx+j, by);});
bx += it_bx;
// while(by < n && examine(bx, by+1)) by++;
d=1;
while(by+d < n && examine(bx, by+d)) d*=2;
ll it_by = last_true(0, d, [&](ll j){return examine(bx, by+j);});
by += it_by;
ll M = bx-ax+1;
ll cx = (ax+bx)/2, cy = (ay+by)/2;
while(cx - M >= 1 && cy - M >= 1 && examine(cx-M, cy-M)) cx-=M, cy-=M;
while(cx - 2*M >= 1 && examine(cx-2*M, cy)) cx-=2*M;
while(cy - 2*M >= 1 && examine(cx, cy-2*M)) cy-=2*M;
cout << "solution " << cx+2*M << " " << cy+2*M << endl;
fflush(stdout);
}
int main(){
ios::sync_with_stdio(false);
cin.tie(0);
solve();
}
