제출 #1338008

#제출 시각아이디문제언어결과실행 시간메모리
1338008jajceslavA Difficult(y) Choice (BOI21_books)C++20
100 / 100
1 ms412 KiB
#include <bits/stdc++.h>

#define ll long long
#define fi first
#define se second
#define mp make_pair

#include "books.h"

using namespace std;
//
// --- Sample implementation for the task books ---
//
// To compile this program with the sample grader, place:
//     books.h books_sample.cpp sample_grader.cpp
// in a single folder and run:
//     g++ books_sample.cpp sample_grader.cpp
// in this folder.
//


void solve(int N, int K, long long A, int S) {

    ll mins[K];
    for(int i = 0; i < K; i++)
    {
        mins[i] = skim(i+1);
    }
    ll sum = 0;
    for(int i = 0; i < K; i++)
        sum += mins[i];

    if(sum > A*2) {
        impossible();
        return;
    }

    if(sum >= A) {
        vector<int> res;
        for(int i = 0; i < K; i++)
            res.push_back(i+1);
        answer(res);
        return;
    }

    // at this point, every element in mins is < 1, so lets find first where >= 1

    int l = K, r = N;
    while(l < r)
    {
        int m = (l+r) / 2;
        ll x = skim(m+1);
        if(x > A)
            r = m;
        else
            l = m+1;
    }

    if(l < N)
    {
        ll big = skim(l+1);
        sum = 0;
        vector<int> res;
        for(int i = 0; i < K-1; i++) {
            sum += mins[i];
            res.push_back(i+1);
        }
        sum += big;
        res.push_back(l+1);
        if(sum <= A*2)
        {
            answer(res);
            return;
        }
    }


    // now we need k maximums or some like that

    vector<pair<int, ll> > fake_arr;
    for(int i = 0; i < K; i++)
    {
        fake_arr.push_back(mp(i, mins[i]));
    }
    for(int i = max(l-K, K); i < l; i++)
    {
        fake_arr.push_back(mp(i, skim(i+1)));
    }

    int n = fake_arr.size();

    // check that max is good
    sum = 0;
    for(int i = n-K; i < n; i++)
    {
        sum += fake_arr[i].se;
    }
    if(sum < A)
    {
        impossible();
    }


    // now min and max are good, ans somewhere in between

    vector<int> res;
    sum = 0;
    for(int i = 0; i < K; i++)
    {
        sum += fake_arr[i].se;
        res.push_back(i);
    }

    for(int i = K-1; i >= 0; i--)
    {
        int nx = (i == K-1) ? n : res[i+1];
        while(res[i] < nx)
        {
            if(sum >= A && sum <= A*2)
            {
                for(int j = 0; j < K; j++)
                {
                    res[j] = fake_arr[res[j]].fi+1;
                }
                answer(res);
                return;
            }
            if(res[i]+1 >= nx)
                break;
            sum -= fake_arr[res[i]].se;
            res[i]++;
            sum += fake_arr[res[i]].se;
        }
    }
    // literally impossible
    assert(0);
}

/*

15 3 42 40
7 8 9 10 11 12 13 14 15 16 17 18 19 20 21

*/
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