제출 #1335886

#제출 시각아이디문제언어결과실행 시간메모리
1335886i271828Hedgehog Daniyar and Algorithms (IZhO19_sortbooks)C++20
64 / 100
2434 ms327680 KiB
#include <bits/stdc++.h>
#define ll long long
#define pii pair<int,int>
using namespace std;

const int MAX=1e6+5;

int N,M;
int A[MAX];
vector<pii> E[MAX]; // {s,qi}
int T[MAX];
int ans[MAX];

struct SRQ{
	int s,e,m,d;
	SRQ *l,*r;
	vector<int> vctl,vctr;
	SRQ(int s,int e):s(s),e(e),m((s+e)/2),d(e-s+1),vctl(vector<int>(d)),vctr(vector<int>(d)){
		vctl.resize(d),vctr.resize(d);
		vector<int> mval(m+1-s); // Max
		int p=0;
		for (int x=m;x>=s;x--) p=max(p,A[x]),mval[m-x]=p;
		
		set<int> se;
		for (int y=m+1;y<=e;y++){
			se.insert(A[y]);
			for (auto [si,qi]:E[y]){
				if (si<s||si>m) continue;
				auto it=se.lower_bound(mval[m-si]);
				if (it==se.begin()) continue;
				it--;
				ans[qi]=max(ans[qi],mval[m-si]+*it);
			}
			auto it=se.lower_bound(p);
			if (it==se.begin()) vctl[y-s]=0;
			else vctl[y-s]=p+*prev(it);
		}
		for (int x=m;x>=s;x--){
			auto it=se.lower_bound(mval[m-x]);
			if (it==se.begin()) vctr[x-s]=0;
			else vctr[x-s]=mval[m-x]+*prev(it);
		}
		mval.clear();
		se.clear();
		
		if (d==1) return;
		
		l=new SRQ(s,m);
		r=new SRQ(m+1,e);
		
		for (int x=s;x<=m;x++){
			vctl[x-s]=max(vctl[x-s],l->vctl[x-l->s]);
			vctr[x-s]=max(vctr[x-s],l->vctr[x-l->s]);
			
			vctr[x-s]=max(vctr[x-s],r->vctr.front());
		}
		
		for (int x=m+1;x<=e;x++){
			vctr[x-s]=max(vctr[x-s],r->vctr[x-r->s]);
			vctl[x-s]=max(vctl[x-s],r->vctl[x-r->s]);
			
			vctl[x-s]=max(vctl[x-s],l->vctl.back());
		}
	}
	
	int qry(int x,int y){
		if (d==1) return 0;
		if (y<=m) return l->qry(x,y);
		if (x>m) return r->qry(x,y);
		return max(l->vctr[x-l->s],r->vctl[y-r->s]);
	}
};

int main(){
	ios::sync_with_stdio(0);cin.tie(0);
	cin>>N>>M;
	for (int i=0;i<N;i++) cin>>A[i];
	for (int qi=0;qi<M;qi++){
		int s,e,k;cin>>s>>e>>k;s--,e--;
		E[e].push_back({s,qi});
		T[qi]=k;
	}
	auto srq=new SRQ(0,N-1);
	for (int e=0;e<N;e++) for (auto [s,qi]:E[e]){
		ans[qi]=max(ans[qi],srq->qry(s,e));
	}
	//for (int i=0;i<M;i++) cout<<ans[i]<<'\n';
	for (int i=0;i<M;i++) cout<<(ans[i]<=T[i])<<'\n';
}
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