제출 #1330192

#제출 시각아이디문제언어결과실행 시간메모리
1330192user736482Tower (JOI24_tower)C++20
0 / 100
72 ms9852 KiB
#pragma GCC optimize("O3")
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define ld long double
#define pb push_back
#define ff first
#define ss second
#define INF 1000000001LL
#define POT (1LL<<23)
#define INFL 1000000000000000099LL
#define pii pair<ll,ll>
#define ppi pair<pii,ll>
#define pip pair<ll,pii>
#define ppp pair<pii,pii>
#define vi vector<ll>
#define vii vector<pii>
#define vvi vector<vi>
#define al(x) x.begin(),x.end()
#define rev(x) reverse(al(x))
#define X 18
#define FCTCST 7
template<typename T, typename U>
pair<T, U> operator+(const pair<T, U>& a, const pair<T, U>& b) {
    return {a.first + b.first, a.second + b.second};
}
template<typename T, typename U>
pair<T, U> operator-(const pair<T, U>& a, const pair<T, U>& b) {
    return {a.first - b.first, a.second - b.second};
}
template<typename T, typename U,typename Z>
pair<T, U> operator*(const pair<T, U>& a, const Z& b) {
    return {a.first*b, a.second*b};
}
template<typename T, typename U,typename Z>
pair<T, U> operator/(const pair<T, U>& a, const Z& b) {
    return {a.first/b, a.second/b};
}
template<typename T, typename U>
ostream& operator<<(ostream& os, const pair<T, U>& p) {
    os<<"{"<<p.ff<<", "<<p.ss<<"}";
    return os;
}
template<typename T>
ostream& operator<<(ostream& os, const vector<T>& v) {
    os << "{";
    for (size_t i = 0; i < v.size(); ++i) {
        if (i) os << ", ";
        os << v[i];
    }
    os << "}";
    return os;
}
template<ll MOD=998244353>
struct mint_t{
    ll x;
    mint_t(ll y=0){x=y%MOD;if(x<0)x+=MOD;}
    mint_t& operator+=(const mint_t& a){if((x+=a.x)>=MOD)x-=MOD;return *this;}
    mint_t& operator-=(const mint_t& a){if((x+=MOD-a.x)>=MOD)x-=MOD;return *this;}
    mint_t operator+(const mint_t& a)const{mint_t res(*this);return res+=a;}
    mint_t operator-(const mint_t& a)const{mint_t res(*this);return res-=a;}
    mint_t& operator*=(const mint_t& a){(x*=a.x)%=MOD;return *this;}
    mint_t operator*(const mint_t& a)const{mint_t res(*this);return res*=a;}
    mint_t fp(ll y)const{
        mint_t a=1,b=x;
        while(y){
            if(y&1)a*=b;
            b*=b;
            y/=2;
        }
        return a;
    }
    mint_t& operator/=(const mint_t& a){(*this)*=a.fp(MOD-2);return *this;}
    mint_t operator/(const mint_t& a)const{mint_t res(*this);return res/=a;}
};
#define mint mint_t<>
template<long long MOD>
istream& operator>>(istream& in, mint_t<MOD>& a){
    ll x;
    in>>x;
    a=mint_t<MOD>(x);
    return in;
}
template<long long MOD>
istream& operator<<(istream& out, mint_t<MOD>& a){
    out<<a.x;
    return out;
}
mint fct[FCTCST];
mint bnm(ll a,ll b){
    if(b>a || a<0)return 0;
    return fct[a]/fct[b]/fct[a-b];
}
ll odp[200007];
void solve(){
    ll n,q,d,a,b,c,e;
    cin>>n>>q>>d>>a>>b;
    vii v;
    vi pm;
    ll p=0;
    for(ll i=0;i<n;i++){
        cin>>c>>e;
        v.pb({p,c-1});
        p=e+1;
    }
    v.pb({p,INFL});
    vii zap;
    for(ll i=0;i<q;i++){
        cin>>c;zap.pb({c,i});pm.pb(c);
    }
    sort(al(zap));rev(zap);
    //cout<<v<<"\n";
    if(d*a<=b){
        queue<ppi>q;
        q.push({v[0],0});
        p=0;
        for(ll i=1;i<=n+1;i++){
            
            while(zap.size() && zap.back().ff<=v[i-1].ss){
                //cout<<v[i-1]<<" "<<zap<<"  ";
                if(zap.back().ff<v[i-1].ff)odp[zap.back().ss]=-1;
                else{
                    odp[zap.back().ss]=p;
                }
                zap.pop_back();
            }
            if(i==n+1)break;
            while(q.size() && q.front().ff.ss+d<v[i].ff)q.pop();
            if(q.empty())q.push({v[i],-INFL}),p=-INFL;
            else q.push({{max(v[i].ff,q.front().ff.ff+d),v[i].ss},++p});//cout<<ppi{{max(v[i].ff,q.front().ff.ff+d),v[i].ss},p}<<" "<<p<<"\n";}
        }
        
    }
    else{
        
    }
    for(ll i=0;i<q;i++){
        if(odp[i]>=0)
        cout<<odp[i]*b+(pm[i]-d*odp[i])*a<<"\n";
        else cout<<-1<<"\n";
    }
}
int main(){
    fct[0]=1;
    for(ll i=1;i<FCTCST;i++)fct[i]=fct[i-1]*i;
    ll t=1;
    //cin>>t;
    for(ll i=1;i<=t;i++){
        //cout<<"Case #"<<i<<": ";
        solve();
    }
}
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