제출 #1329392

#제출 시각아이디문제언어결과실행 시간메모리
1329392Nonoze축제 (IOI25_festival)C++20
70 / 100
62 ms10284 KiB
#include "festival.h"
#include <bits/stdc++.h>
using namespace std;

#ifndef DEBUG
	#define dbg(...)
#endif

// #define cout cerr << "OUT: "
#define endl '\n'
#define endlfl '\n' << flush
#define quit(x) return (void)(cout << x << endl)

template<typename T> void read(T& x) { cin >> x; }
template<typename T1, typename T2> void read(pair<T1, T2>& p) { read(p.first), read(p.second); }
template<typename T> void read(vector<T>& v) { for (auto& x : v) read(x); }
template<typename T1, typename T2> void read(T1& x, T2& y) { read(x), read(y); }
template<typename T1, typename T2, typename T3> void read(T1& x, T2& y, T3& z) { read(x), read(y), read(z); }
template<typename T1, typename T2, typename T3, typename T4> void read(T1& x, T2& y, T3& z, T4& zz) { read(x), read(y), read(z), read(zz); }
template<typename T> void print(vector<T>& v) { for (auto& x : v) cout << x << ' '; cout << endl; }

#define sz(x) (int)(x.size())
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define make_unique(v) sort(all(v)), v.erase(unique(all(v)), (v).end())
#define pb push_back
#define mp(a, b) make_pair(a, b)
#define fi first
#define se second
#define cmin(a, b) a = min(a, b)
#define cmax(a, b) a = max(a, b)
#define YES cout << "YES" << endl
#define NO cout << "NO" << endl
#define QYES quit("YES")
#define QNO quit("NO")

#define int long long
#define double long double
const int inf = numeric_limits<int>::max() / 4;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int MOD = 1e9+7, LOG=20;


vector<signed> calc(vector<signed> ans, vector<vector<pair<int, int>>>& vals) {
	vector<signed> res;
	for (auto& x : ans) res.pb(x);
	for (int i=0; i<4; i++) for (auto& [p, id] : vals[i]) res.pb(id);
	return res;
}


vector<signed> max_coupons(signed AA, vector<signed> P, vector<signed> T) {
	int n=sz(P), A=AA;
	vector<vector<pair<int, int>>> vals(4);
	for (int i=0; i<sz(P); i++) {
		vals[T[i]-1].pb({P[i], i});
	}
	for (int i=0; i<4; i++) sort(rall(vals[i]));

	vector<signed> ans;

	while (n--) {
		int best=inf, act=0;
		vector<int> v;
		for (int i=1; i<4; i++) if (!vals[i].empty() && (A-vals[i].back().fi)*(i+1)>A) {
			v.pb(i);
		}
		if (v.empty()) break;
		do {
			int sum=0;
			for (int i=0; i<sz(v); i++) {
				int cur=vals[v[i]].back().fi;
				for (int j=i; j<sz(v); j++) {
					cur*=(v[j]+1);
				}
				sum+=cur;
			}
			if (sum<best) best=sum, act=v[0];
		} while (next_permutation(all(v)));

		A=(A-vals[act].back().fi)*(act+1);
		assert(A>=0);
		ans.pb(vals[act].back().se);
		vals[act].pop_back();
		if (A>=1e12) return calc(ans, vals);
	}
	for (int i=0; i<4; i++) while (!vals[i].empty() && (A-vals[i].back().fi)*(i+1)==A){
		ans.pb(vals[i].back().se);
		vals[i].pop_back();
	}
	for (auto &u: vals) reverse(all(u));

	vector<int> pref0; if (!vals[0].empty()) pref0.pb(vals[0][0].fi);
	for (int i=1; i<sz(vals[0]); i++) pref0.pb(pref0[i-1]+vals[0][i].fi);

	int m1=min(sz(vals[1]), 40LL)+1, m2=min(sz(vals[2]), 40LL)+1, m3=min(sz(vals[3]), 40LL)+1;

	vector<vector<vector<int>>> dp(m1, vector<vector<int>>(m2, vector<int>(m3, -1))); dp[0][0][0]=A;
	int best=0;
	vector<int> besti(3);
	for (int i=0; i<m1; i++) {
		for (int j=0; j<m2; j++) {
			for (int k=0; k<m3; k++) {
				if (i) cmax(dp[i][j][k], (dp[i-1][j][k] - vals[1][i-1].fi)*2);
				if (j) cmax(dp[i][j][k], (dp[i][j-1][k] - vals[2][j-1].fi)*3);
				if (k) cmax(dp[i][j][k], (dp[i][j][k-1] - vals[3][k-1].fi)*4);
				if (dp[i][j][k]<0) continue;
				auto lb=upper_bound(all(pref0), dp[i][j][k]) - pref0.begin();
				if (i+j+k+lb>best) {
					best=i+j+k+lb;
					besti={i, j, k};
					dbg(i, j, k, lb);
				}
			}
		}
	}
	vector<int> vec(1, 0);

	if (best==0) return ans;

	vector<signed> res;

	for (int i=0; i<best - besti[0] - besti[1] - besti[2]; i++) res.pb(vals[0][i].se);
	reverse(all(res));

	best=besti[0]+besti[1]+besti[2];
	while (best--) {
		int i=besti[0], j=besti[1], k=besti[2];
		if (i && dp[i][j][k]==(dp[i-1][j][k] - vals[1][i-1].fi)*2) {
			res.pb(vals[1][i-1].se);
			besti[0]--;
		} else if (j && dp[i][j][k]==(dp[i][j-1][k] - vals[2][j-1].fi)*3) {
			res.pb(vals[2][j-1].se);
			besti[1]--;
		} else {
			res.pb(vals[3][k-1].se);
			besti[2]--;
		}
	}

	reverse(all(res));
	ans.insert(ans.end(), all(res));

	return ans;
}
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