답안 #132822

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
132822 2019-07-19T16:53:39 Z youngyojun Dragon 2 (JOI17_dragon2) C++11
60 / 100
4000 ms 7292 KB
#include <bits/stdc++.h>
#define eb emplace_back
#define sz(V) ((int)(V).size())
#define allv(V) ((V).begin()),((V).end())
#define sorv(V) sort(allv(V))
#define rb(x) ((x)&(-(x)))
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
pll operator + (const pll &a, const pll &b) { return pll(a.first+b.first, a.second+b.second); }
pll operator - (const pll &a, const pll &b) { return pll(a.first-b.first, a.second-b.second); }
ll operator * (const pll &a, const pll &b) { return a.first*b.second - b.first*a.second; }
ll ccw(const pll &a, const pll &b, const pll &c) { return a*b + b*c + c*a; }

const int MAXN = 30005;
const int MAXK = 30005;
const int MAXQ = 100005;
const int MX = 60055;

struct EVT {
	EVT(int p, int x, int i) : p(p), x(x), i(i) {}
	int p, x, i;

	bool operator < (const EVT &t) const {
		if(x != t.x) return x < t.x;
		return p < t.p;
	}
};

struct BIT {
	int d[MX];
	void init() { memset(d, 0, MX<<2); }
	void init(int x) {
		for(x += 5; x < MX; x += rb(x))
			d[x] = 0;
	}
	void upd(int x, int r) {
		for(x += 5; x < MX; x += rb(x))
			d[x] += r;
	}
	int get(int x) {
		int r = 0; for(x += 5; x; x -= rb(x))
			r += d[x];
		return r;
	}
	int get(int s, int e) { return s > e ? 0 : get(e)-get(s-1); }
} bit;

pll P[MAXN*2];
int A[MAXN], O[MAXN*2];

vector<int> AV[MAXK];
int L[MAXN], LS[MAXN], LE[MAXN];
int R[MAXN], RS[MAXN], RE[MAXN];
int B[MAXQ], C[MAXQ];

int Ans[MAXQ];
int N, K, Q;

void cal(int a, int b, int &ret) {
	vector<EVT> EV;
	for(int v : AV[b]) EV.eb(0, L[v], v);
	for(int v : AV[a]) {
		EV.eb(1, LS[v]-1, v);
		EV.eb(2, LE[v], v);
	}
	sorv(EV);
	for(auto &ev : EV) {
		int t = ev.p, i = ev.i;
		if(!t) bit.upd(R[i], 1);
		else if(1 == t) ret -= bit.get(RS[i], RE[i]);
		else ret += bit.get(RS[i], RE[i]);
	}
	for(int v : AV[b]) bit.init(R[v]);
}

void precal() {
	iota(O, O+(N<<1), 4);
	for(int i = 0; i <= N+1; i++)
		P[i<<1|1] = P[0] + P[0] - P[i<<1];
	sort(O, O+(N<<1), [&](int a, int b) {
		bool af = ccw(P[3], P[0], P[a]) < 0;
		bool bf = ccw(P[3], P[0], P[b]) < 0;
		if(af != bf) return af;
		return ccw(P[a], P[0], P[b]) < 0;
	});
	for(int i = 0, v; i < N; i++) {
		v = O[i];
		L[(v>>1)-1] = i + ((v&1) ? N : 0);
		v >>= 1; v--;
		LS[v] = i; LE[v] = i+N;
	}
	for(int i = 0; i <= N+1; i++)
		P[i<<1|1] = P[2] + P[2] - P[i<<1];
	sort(O, O+(N<<1), [&](int a, int b) {
		bool af = ccw(P[1], P[2], P[a]) < 0;
		bool bf = ccw(P[1], P[2], P[b]) < 0;
		if(af != bf) return af;
		return ccw(P[a], P[2], P[b]) < 0;
	});
	for(int i = 0, v; i < N; i++) {
		v = O[i];
		R[(v>>1)-1] = i + ((v&1) ? N : 0);
		v >>= 1; v--;
		RS[v] = i; RE[v] = i+N;
	}
	for(int i = 1; i <= N; i++) {
		L[i]++; LS[i]++; LE[i]++;
		R[i]++; RS[i]++; RE[i]++;
	}
}

int main() {
	ios::sync_with_stdio(false);

	cin >> N >> K;
	for(int i = 1; i <= N; i++) {
		cin >> P[(i+1)<<1].first >> P[(i+1)<<1].second >> A[i];
		AV[A[i]].eb(i);
	}
	cin >> P[0].first >> P[0].second >> P[2].first >> P[2].second;
	cin >> Q;
	for(int i = 1; i <= Q; i++) cin >> B[i] >> C[i];

	precal();

	for(int i = 1; i <= Q; i++) cal(B[i], C[i], Ans[i]);

	for(int i = 1; i <= Q; i++) printf("%d\n", Ans[i]);
	return 0;
}
# 결과 실행 시간 메모리 Grader output
1 Correct 7 ms 1528 KB Output is correct
2 Correct 12 ms 1404 KB Output is correct
3 Correct 52 ms 1528 KB Output is correct
4 Correct 121 ms 3624 KB Output is correct
5 Correct 69 ms 3708 KB Output is correct
6 Correct 7 ms 1660 KB Output is correct
7 Correct 7 ms 1528 KB Output is correct
8 Correct 7 ms 1528 KB Output is correct
9 Correct 6 ms 1528 KB Output is correct
10 Correct 6 ms 1524 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 57 ms 4788 KB Output is correct
2 Correct 122 ms 4496 KB Output is correct
3 Correct 63 ms 4216 KB Output is correct
4 Correct 52 ms 4216 KB Output is correct
5 Correct 54 ms 4600 KB Output is correct
6 Correct 47 ms 4900 KB Output is correct
7 Correct 47 ms 4900 KB Output is correct
8 Correct 55 ms 4860 KB Output is correct
9 Correct 41 ms 4644 KB Output is correct
10 Correct 43 ms 4660 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 7 ms 1528 KB Output is correct
2 Correct 12 ms 1404 KB Output is correct
3 Correct 52 ms 1528 KB Output is correct
4 Correct 121 ms 3624 KB Output is correct
5 Correct 69 ms 3708 KB Output is correct
6 Correct 7 ms 1660 KB Output is correct
7 Correct 7 ms 1528 KB Output is correct
8 Correct 7 ms 1528 KB Output is correct
9 Correct 6 ms 1528 KB Output is correct
10 Correct 6 ms 1524 KB Output is correct
11 Correct 57 ms 4788 KB Output is correct
12 Correct 122 ms 4496 KB Output is correct
13 Correct 63 ms 4216 KB Output is correct
14 Correct 52 ms 4216 KB Output is correct
15 Correct 54 ms 4600 KB Output is correct
16 Correct 47 ms 4900 KB Output is correct
17 Correct 47 ms 4900 KB Output is correct
18 Correct 55 ms 4860 KB Output is correct
19 Correct 41 ms 4644 KB Output is correct
20 Correct 43 ms 4660 KB Output is correct
21 Correct 59 ms 4788 KB Output is correct
22 Correct 120 ms 4468 KB Output is correct
23 Correct 725 ms 4476 KB Output is correct
24 Correct 1153 ms 6840 KB Output is correct
25 Correct 186 ms 6648 KB Output is correct
26 Correct 128 ms 7060 KB Output is correct
27 Correct 51 ms 5368 KB Output is correct
28 Correct 54 ms 5240 KB Output is correct
29 Execution timed out 4003 ms 7292 KB Time limit exceeded
30 Halted 0 ms 0 KB -