Submission #1319860

#	Time	Username	Problem	Language	Result	Execution time	Memory
1319860		zyntherix	Self Study (JOI22_ho_t2)	C++20	0 / 100	1 ms	332 KiB

Main

#include <bits/stdc++.h>
using namespace std;
#define int long long
#define pi pair<int, int>
#define vi vector<int>
#define vs vector<string>
#define vb vector<bool>
#define vpi vector<pi>
#define pb push_back
#define all(a) (a).begin(), (a).end()
const int mod = 1e9 + 7;

void solve()
{
    int n, m;
    cin >> n >> m;
    int a[n], b[n];
    multiset<pi> ms;
    for (int i = 0; i < n; i++)
    {
        cin >> a[i];
        ms.insert({m * a[i], a[i]});
    }
    for (int i = 0; i < n; i++)
        cin >> b[i];
    for (int k = 0; k < n+(10000); k++)
    {
        pi sm = *ms.begin();
        pi bg = *ms.rbegin();
        ms.erase(ms.begin());
        ms.erase(prev(ms.end()));
        int l = 0;
        int r = bg.first / bg.second;
        while (l + 1 < r)
        {
            int md = (l + r) / 2;
            if ((md * sm.second) + sm.first >= bg.first - (bg.second * md))
            {
                r = md;
            }
            else
            {
                l = md;
            }
        }
        pi p = {(l * sm.second) + sm.first, bg.first - (bg.second * l)};
        pi q = {(r * sm.second) + sm.first, bg.first - (bg.second * r)};
        if (min(p.first, p.second) > min(q.first, q.second))
        {
            pi sm2 = {p.first, sm.second};
            pi bg2 = {p.second, bg.second};
            ms.insert(sm2);
            ms.insert(bg2);
        }
        else
        {
            pi sm2 = {q.first, sm.second};
            pi bg2 = {q.second, bg.second};
            ms.insert(sm2);
            ms.insert(bg2);
        }
    }
    cout << ms.begin()->first << '\n';
}

signed main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(NULL);
    cout.tie(NULL);
    int t = 1;
    // cin >> t;
    while (t--)
    {
        solve();
    }
    return 0;
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 25
• Subtask 3: 0 / 27
• Subtask 4: 0 / 29
• Subtask 5: 0 / 9