Submission #131643

#	Time	Username	Problem	Language	Result	Execution time	Memory
131643		SirCeness	Naan (JOI19_naan)	C++14	29 / 100	293 ms	9052 KiB

naan

#include <bits/stdc++.h>
 
using namespace std;
#define mod 1000000007
#define mp make_pair
#define pb push_back
#define bas(x) #x << ": " << x
#define prarr(x, n) cout << #x << ": "; for (int qsd = 0; qsd < n; qsd++) cout << x[qsd] << " "; cout << endl;
#define prarrv(x) cout << #x << ": "; for (int qsd = 0; qsd < (int)x.size(); qsd++) cout << x[qsd] << " "; cout << endl;
#define inside sl<=l%&&r<=sr
#define outside sr<l||r<sl
 
typedef long long ll;
 
int n, m;
ll mat[2002][2002];
ll presum[2002][2002];
 
pair<ll, ll> sum(pair<ll, ll> a, pair<ll, ll> b){
	ll pay = a.first*b.second + a.second*b.first;
	ll payda = a.second*b.second;
	ll gcd = __gcd(pay, payda);
	pay /= gcd;
	payda /= gcd;
	/*while (payda > 1000000000){
		pay++;
		gcd = __gcd(pay, payda);
		pay /= gcd;
		payda /= gcd;
	}*/
	return mp(pay, payda);
}
 
 
pair<ll, ll> get(int i, ll pay, ll payda){
	//cout << "get(" << i << ", " << pay << ", "  << payda << ")" << endl;
	/*double ans = presum[i][(int)(pay/payda)-1];
	ans += mat[i][(int)(pay/payda)]*((pay/payda) - (int)(pay/payda));
	return ans;*/
	return sum(mp(presum[i][(pay/payda)-1], 1), mp((pay%payda)*mat[i][pay/payda], payda));
}
 
pair<ll, ll> getmin(int i, pair<ll, ll> puan){
	//cout << "getmin(" << i << ", " << puan.first << ", " << puan.second << ")" << endl;
	if (presum[i][m-1] < (double)puan.first/(double)puan.second) return mp(-1, -1);
	int l = -1;
	int r = m-1;
	while (l < r){
		int m = (l+r+1)/2;
		if (presum[i][m] > (double)puan.first/(double)puan.second) r = m-1;
		else l = m;
	}
	//cout << bas(l) << endl;
	if (l != -1 && presum[i][l] == (double)puan.first/(double)puan.second) return mp(l+1, 1);
	puan = sum(puan, mp((l == -1) ? 0 : -presum[i][l], 1));
	// mat[i][l+1]*oran = puan;
	return sum(mp(l+1, 1), mp(puan.first, puan.second*mat[i][l+1]));
}
 
int main(){
	cin.tie(0); ios::sync_with_stdio(false);
	cin >> n >> m;
	for (int i = 0; i < n; i++){
		ll cur = 0;
		for (int j = 0; j < m; j++){
			cin >> mat[i][j];
			cur += mat[i][j];
			presum[i][j] = cur;
		}
	}
	
	/*for (int i = 0; i < n; i++){
		for (int j = 0; j < m; j++){
			cout << mat[i][j] << " ";
		}
		cout << endl;
	}
	cout << endl;
	
	for (int i = 0; i < n; i++){
		for (int j = 0; j < m; j++){
			cout << presum[i][j] << " ";
		}
		cout << endl;
	}
	cout << endl;*/
	
	vector<pair<ll, ll> > ans;
	vector<int> p;
	bitset<2002> vis;
	vis.reset();
	
	ll cpay = 0;
	ll cpayda = 1;
	for (int bol = 0; bol < n; bol++){
		//cout << bas(bol) << endl;
		ll minpay = 10000000;
		ll minpayda = 1;
		int ci = 0;
		for (int i = 0; i < n; i++){
			if (vis[i]) continue;
			//cout << bas(i) << endl;
			pair<ll, ll> suan = get(i, cpay, cpayda);
			//cout << "suan: " << suan.first << ", " << suan.second << endl;
			pair<ll, ll> minoran = getmin(i, sum(suan, mp(presum[i][m-1], n)));
			//cout << bas(minoran.first) << ", " << bas(minoran.second) << endl;
			if (minoran.first == -1){
				cout << -1 << endl;
				exit(0);
			}
			if ((double)minpay/(double)minpayda >(double) minoran.first/(double)minoran.second){
				minpay = minoran.first;
				minpayda = minoran.second;
				ci = i;
			}
		}
		
		cpay = minpay;
		cpayda = minpayda;
		
		ans.pb(mp(cpay, cpayda));
		p.pb(ci+1);
		vis[ci] = 1;
		//cout << cpay << " " << cpayda << " -> " << ci << endl;
	}
	
	for (int i = 0; i < n-1; i++) cout << ans[i].first << " " << ans[i].second << endl;
	for (int i = 0; i < n; i++) cout << p[i] << " ";
	cout << endl;
}

• Subtask 1: 5 / 5
• Subtask 2: 24 / 24
• Subtask 3: 0 / 71