제출 #1313983

#제출 시각아이디문제언어결과실행 시간메모리
1313983thieunguyenhuyArt Collections (BOI22_art)C++20
100 / 100
681 ms480 KiB
#ifndef hwe #include "art.h" #endif #include <bits/stdc++.h> using namespace std; #define POPCOUNT(n) (__builtin_popcountll((n))) #define CLZ(n) (__builtin_clzll((n))) #define CTZ(n) (__builtin_ctzll((n))) #define LOG(n) (63 - __builtin_clzll((n))) #define BIT(n, i) (((n) >> (i)) & 1ll) #define MASK(i) (1ll << (i)) #define FLIP(n, i) ((n) ^ (1ll << (i))) #define ON(n, i) ((n) | MASK(i)) #define OFF(n, i) ((n) & ~MASK(i)) #define Int __int128 #define fi first #define se second typedef long long ll; typedef unsigned long long ull; typedef long double ld; typedef pair<int, int> pii; typedef pair<long long, long long> pll; typedef pair<long long, int> pli; typedef pair<int, long long> pil; typedef vector<pair<int, int>> vii; typedef vector<pair<long long, long long>> vll; typedef vector<pair<long long, int>> vli; typedef vector<pair<int, long long>> vil; template <class T1, class T2> bool maximize(T1 &x, T2 y) { if (x < y) { x = y; return true; } return false; } template <class T1, class T2> bool minimize(T1 &x, T2 y) { if (x > y) { x = y; return true; } return false; } template <class T> void remove_duplicate(vector<T> &ve) { sort (ve.begin(), ve.end()); ve.resize(unique(ve.begin(), ve.end()) - ve.begin()); } mt19937_64 rng(chrono::high_resolution_clock::now().time_since_epoch().count()); long long random(long long l, long long r) { return uniform_int_distribution<long long>(l, r)(rng); } template <class T> T random(T r) { return rng() % r; } const int N = 1e6 + 5; const int MOD = 1e9 + 7; const int inf = 1e9; const long long INF = 1e18; #ifdef hwe int n; vector<int> A; int publish(vector<int> R) { vector<int> pos(n + 1); for (int i = 0; i < A.size(); ++i) pos[A[i]] = i; int ans = 0; for (int i = 0; i < R.size(); ++i) for (int j = i + 1; j < R.size(); ++j) { if (pos[R[i]] > pos[R[j]]) ++ans; } return ans; } void answer(vector<int> R) { cerr << "answer "; for (auto &x : R) cerr << x << ' '; cerr << '\n'; } #endif void solve(int n) { vector<int> p(n); iota(p.begin(), p.end(), 1); vector<int> inv(n), ans(n); for (int i = 0; i < n; ++i) { inv[i] = publish(p); rotate(p.begin(), p.begin() + 1, p.end()); // cerr << inv[i] << ' '; } // cerr << '\n'; // for (auto &x : p) cerr << x << ' '; // cerr << '\n'; for (int i = 0; i < n; ++i) { int nxt = (i == n - 1 ? 0 : i + 1); int idx = (n - 1 - (inv[nxt] - inv[i])) / 2; ans[idx] = p[i]; } answer(ans); } #ifdef hwe signed main() { cin >> n; A.assign(n, 0); for (auto &x : A) cin >> x; solve(n); return 0; } #endif
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