제출 #1313368

#제출 시각아이디문제언어결과실행 시간메모리
1313368thieunguyenhuypopa (BOI18_popa)C++20
37 / 100
77 ms412 KiB
#ifndef hwe #include "popa.h" #endif #include <bits/stdc++.h> using namespace std; #define POPCOUNT(n) (__builtin_popcountll((n))) #define CLZ(n) (__builtin_clzll((n))) #define CTZ(n) (__builtin_ctzll((n))) #define LOG(n) (63 - __builtin_clzll((n))) #define BIT(n, i) (((n) >> (i)) & 1ll) #define MASK(i) (1ll << (i)) #define FLIP(n, i) ((n) ^ (1ll << (i))) #define ON(n, i) ((n) | MASK(i)) #define OFF(n, i) ((n) & ~MASK(i)) #define Int __int128 #define fi first #define se second typedef long long ll; typedef unsigned long long ull; typedef long double ld; typedef pair<int, int> pii; typedef pair<long long, long long> pll; typedef pair<long long, int> pli; typedef pair<int, long long> pil; typedef vector<pair<int, int>> vii; typedef vector<pair<long long, long long>> vll; typedef vector<pair<long long, int>> vli; typedef vector<pair<int, long long>> vil; template <class T1, class T2> bool maximize(T1 &x, T2 y) { if (x < y) { x = y; return true; } return false; } template <class T1, class T2> bool minimize(T1 &x, T2 y) { if (x > y) { x = y; return true; } return false; } template <class T> void remove_duplicate(vector<T> &ve) { sort (ve.begin(), ve.end()); ve.resize(unique(ve.begin(), ve.end()) - ve.begin()); } mt19937_64 rng(chrono::high_resolution_clock::now().time_since_epoch().count()); long long random(long long l, long long r) { return uniform_int_distribution<long long>(l, r)(rng); } template <class T> T random(T r) { return rng() % r; } const int N = 1000 + 5; const int MOD = 1e9 + 7; const int inf = 1e9; const long long INF = 1e18; #ifdef hwe int S[N]; int query(int l, int r, int u, int v) { int g1 = 0, g2 = 0; for (int i = l; i <= r; ++i) g1 = __gcd(g1, S[i]); for (int i = u; i <= v; ++i) g2 = __gcd(g2, S[i]); return g1 == g2; } #endif int solve(int n, int *Left, int *Right) { Left[0] = Right[0] = -1; int root = 0; for (int i = 1; i < n; ++i) { if (query(root, i, i, i)) Left[i] = root, Right[i] = -1, root = i; else { int p = root; while (true) { if (Right[p] == -1) { Right[p] = i, Left[i] = Right[i] = -1; break; } if (query(Right[p], i, i, i)) { Left[i] = Right[p], Right[p] = i, Right[i] = -1; break; } p = Right[p]; } } } return root; } #ifdef hwe int L[N], R[N]; signed main() { int n; cin >> n; for (int i = 0; i < n; ++i) cin >> S[i]; cerr << "root = " << solve(n, L, R) << '\n'; for (int i = 0; i < n; ++i) cerr << i << ' ' << L[i] << ' ' << R[i] << '\n'; return 0; } #endif
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