제출 #1313342

#제출 시각아이디문제언어결과실행 시간메모리
1313342Zbyszek99Popeala (CEOI16_popeala)C++20
100 / 100
112 ms24452 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #define ll long long #define ld long double #define ull unsigned long long #define ff first #define ss second #define pii pair<int,int> #define pll pair<long long, long long> #define vi vector<int> #define vl vector<long long> #define pb push_back #define rep(i, b) for(int i = 0; i < (b); ++i) #define rep2(i,a,b) for(int i = a; i <= (b); ++i) #define rep3(i,a,b,c) for(int i = a; i <= (b); i+=c) #define count_bits(x) __builtin_popcountll((x)) #define all(x) (x).begin(),(x).end() #define siz(x) (int)(x).size() #define forall(it,x) for(auto& it:(x)) using namespace __gnu_pbds; using namespace std; typedef tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update> ordered_set; //mt19937 mt;void random_start(){mt.seed(chrono::time_point_cast<chrono::milliseconds>(chrono::high_resolution_clock::now()).time_since_epoch().count());} //ll los(ll a, ll b) {return a + (mt() % (b-a+1));} const int INF = 1e9+50; const ll INF_L = 1e18+40; const ll MOD = 1e9+7; ll pref[20001]; bool can_solve[50][20001]; int nxt_zero[50][20001]; ll best[51][51]; ll dp[20001][51]; vector<pii> events[20003]; int main() { ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0); //random_start(); int n,t,s; cin >> n >> t >> s; rep2(i,1,t) { ll x; cin >> x; pref[i] = pref[i-1]+x; } rep(i,n) { can_solve[i][0] = 1; rep2(j,1,t) { char z; cin >> z; can_solve[i][j] = z-'0'; } int pop = t+1; for(int j = t; j >= 0; j--) { if(!can_solve[i][j]) pop = j; nxt_zero[i][j] = pop; } } rep2(i,0,t-1) { vi x; rep(j,n) x.pb(nxt_zero[j][i+1]); sort(all(x)); rep(j,n) events[x[j]].pb({i,n-j-1}); } rep2(i,0,t) rep2(j,0,s) dp[i][j] = 1e18; rep2(i,0,s) rep2(j,0,n) best[i][j] = 1e18; best[0][n] = 0; dp[0][0] = 0; rep2(i,1,t) { forall(it,events[i]) { rep(j,s+1) best[j][it.ss] = min(best[j][it.ss],dp[it.ff][j]-pref[it.ff]*it.ss); } rep2(j,1,s) { rep(k,n+1) { dp[i][j] = min(dp[i][j],best[j-1][k]+pref[i]*k); } } rep2(j,1,s) best[j][n] = min(best[j][n],dp[i][j]-pref[i]*n); } rep2(i,1,s) cout << dp[t][i] << "\n"; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...