제출 #1311768

#제출 시각아이디문제언어결과실행 시간메모리
1311768thelegendary08The Xana coup (BOI21_xanadu)C++17
0 / 100
39 ms20700 KiB
#include<bits/stdc++.h> // #include<atcoder/modint> // #include<atcoder/convolution> #define pb push_back #define eb emplace_back #define mp make_pair #define F first #define S second #define rs resize #define ft front() #define bk back() #define int long long #define vi vector<int> #define vvi vector<vector<int>> #define pii pair<int, int> #define vpii vector<pair<int, int>> #define vc vector<char> #define vb vector<bool> #define mii map<int,int> #define f0r(i,n) for(int i=0;i<n;i++) #define FOR(i,k,n) for(int i=k;i<n;i++) #define r0f(i,n) for(int i = n-1; i >= 0; i--) #define R0F(i,k,n) for(int i = n-1; i >= k; i--) #define all(v) (v).begin(),(v).end() #define rall(v) (v).rbegin(),(v).rend() #define SUM(v) (accumulate(all(v), 0LL)) #define in(a) int a; cin>>a #define in2(a,b) int a,b; cin>>a>>b #define in3(a,b,c) int a,b,c; cin>>a>>b>>c #define in4(a,b,c,d) int a,b,c,d; cin>>a>>b>>c>>d #define vin(v,n); vi v(n); f0r(i,n){cin>>v[i];} #define out(a) cout<<a<<'\n' #define out2(a,b) cout<<a<<' '<<b<<'\n' #define out3(a,b,c) cout<<a<<' '<<b<<' '<<c<<'\n' #define out4(a,b,c,d) cout<<a<<' '<<b<<' '<<c<<' '<<d<<'\n' #define pout(a) cout<<a.first<<' '<<a.second<<'\n' #define vout(v) for(auto u : v){cout<<u<<' ';} cout<<endl #define dout(a) cout<<a<<' '<<#a<<endl #define dout2(a,b) cout<<a<<' '<<#a<<' '<<b<<' '<<#b<<endl #define YN(x); if(x){cout<<"YES"<<'\n';}else{cout<<"NO"<<'\n';} #define yn(x); if(x){cout<<"Yes"<<'\n';}else{cout<<"No"<<'\n';} #define p2(x) (1LL << (x)) #define pct(x) (__builtin_popcountll((x))) #define ist(x,y) (((x) >> (y)) & 1) template<class T, class U> bool ckmin(T& a, const U& b) { return (T)b < a ? a = (T)b, 1 : 0; } template<class T, class U> bool ckmax(T& a, const U& b) { return a < (T)b ? a = (T)b, 1 : 0; } const int leg = 1e9 + 7; const int mod = 998244353; using namespace std; // using namespace atcoder; // using mint = modint998244353; // using mint = modint1000000007; const int mxn = 1e5 + 5; // mint fact[mxn], inv[mxn]; // mint C(int n, int r){return fact[n] * inv[n-r] * inv[r];} // mint snb(int n, int r){return C(n + r, n);} vi adj[mxn]; int col[mxn], dp[mxn][2][2]; void dfs(int node, int from){ for(auto u : adj[node])if(u!=from){ dfs(u,node); } f0r(x,2){ col[node] ^= x; f0r(y,2){ //y=1 means take x = 0 for children, otherwise take x = 1 int dif = 1e9, sum = 0, xo = col[node] ^ y; bool ok = 1; for(auto u : adj[node])if(u!=from){ if(dp[u][y][0] == 1e9 && dp[u][y][1] == 1e9)ok=0; else if(dp[u][y][0] < dp[u][y][1])sum += dp[u][y][0]; else sum += dp[u][y][1], xo ^= 1; if(dp[u][y][0] != 1e9 && dp[u][y^1][1] != 1e9)ckmin(dif, abs(dp[u][y][0]-dp[u][y][1])); } if(!ok)continue; if(xo==0)dp[node][x][y] = sum + y; else if(dif == 1e9)continue; else dp[node][x][y] = sum + dif + y; } col[node] ^= x; } } signed main(){ ios::sync_with_stdio(false); cin.tie(NULL); //ifstream cin(".in"); //ofstream cout(".out"); // fact[0]=1;FOR(i,1,mxn)fact[i]=fact[i-1]*i;inv[mxn-1]=fact[mxn-1].inv();r0f(i,mxn-1)inv[i]=inv[i+1]*(i+1); int n; cin>>n; f0r(i,n-1){in2(a,b);a--;b--;adj[a].pb(b);adj[b].pb(a);} f0r(i,n)cin>>col[i]; f0r(i,n)f0r(j,2)f0r(k,2)dp[i][j][k]=1e9; dfs(0,-1); int ans = min(dp[0][0][0],dp[0][0][1]); if(ans==1e9)out("impossible"); else out(ans); }
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