Submission #1311678

#TimeUsernameProblemLanguageResultExecution timeMemory
1311678thelegendary08도로 폐쇄 (APIO21_roads)C++20
7 / 100
2097 ms66724 KiB
#include "roads.h" #include<bits/stdc++.h> #define int long long #define mp make_pair #define eb emplace_back #define pb push_back #define f0r(i,n) for(int i = 0; i < n; i++) #define FOR(i,k,n) for(int i = k; i < n; i++) #define vi vector<int> #define vvi vector<vi> #define dout(x) cout<<x<<' '<<#x<<endl; #define dout2(x,y) cout<<x<<' '<<#x<<' '<<y<<' '<<#y<<endl; #define vout(v) for(auto u : v)cout<<u<<' '; cout<<endl; using namespace std; const int mxn = 1e5 + 5; struct Edge{ int u,v,w; }; set<pair<int,int>>adj[mxn]; vector<pair<int,int>>G[mxn]; int n, k; int dp[mxn][2]; multiset<int, greater<int>>dif[mxn]; bool vis[mxn]; set<int>imp; void dfs(int node, int from){ vis[node]=1; int sum = 0; for(auto [u,w] : adj[node])if(u!=from)dfs(u,node), sum+=max(dp[u][0],dp[u][1]), dif[node].insert(dp[u][0]+w-max(dp[u][0],dp[u][1])); dp[node][1]=sum; int cnt = 0; for(auto u : dif[node]){ if(cnt==k)break; dp[node][1]+=u; cnt++; } dp[node][0]=sum; cnt = 0; for(auto u : dif[node]){ if(cnt>=k-1)break; dp[node][0]+=u; cnt++; } for(auto [u,w] : adj[node])dif[node].erase(dp[u][0]+w-max(dp[u][0],dp[u][1])); } std::vector<long long> minimum_closure_costs(signed N, std::vector<signed> U, std::vector<signed> V, std::vector<signed> W) { n=N; vi ans; int S = 0; vi deg(n); vector<Edge>edges; f0r(i,n-1)edges.pb({U[i],V[i],W[i]}),adj[U[i]].insert(mp(V[i],W[i])),adj[V[i]].insert(mp(U[i],W[i])),G[U[i]].eb(V[i],W[i]),G[V[i]].eb(U[i],W[i]),S+=W[i],deg[U[i]]++,deg[V[i]]++; vvi w(n); f0r(i,n)w[deg[i]].pb(i); f0r(i,n)imp.insert(i); int per = 0; vi plus(n); for(auto [u,v,w] : edges){ plus[max(deg[u],deg[v])]+=w; } f0r(K,n){ k=K; per+=plus[k]; vi tmp; for(auto u : w[k]){ imp.erase(u); tmp.pb(u); } vector<pair<pair<int,int>,int>>er; for(auto u : tmp){ for(auto [x,w] : adj[u]){if(imp.count(x))dif[x].insert(w); er.pb(mp(mp(u,x),w));} } for(auto idk : er){ int u = idk.first.first, v = idk.first.second, w = idk.second; adj[u].erase(mp(v,w)); adj[v].erase(mp(u,w)); } //vout(imp); for(auto i : imp)f0r(j,2)dp[i][j]=0, vis[i]=0; int cur = S-per; //dout(per); for(auto i : imp)if(!vis[i])dfs(i,-1), cur -= max(dp[i][0],dp[i][1]); ans.pb(cur); } return ans; }
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