Submission #1311292

#	Time	Username	Problem	Language	Result	Execution time	Memory
1311292		syanvu	Vinjete (COI22_vinjete)	C++20	100 / 100	656 ms	262188 KiB

Main

// #pragma optimize ("g",on)
// #pragma GCC optimize ("inline")
// #pragma GCC optimize ("Ofast")
// #pragma GCC optimize ("unroll-loops")
// #pragma GCC optimize ("03")
#include <bits/stdc++.h>

#define pb push_back
#define SS ios_base::sync_with_stdio(0);cin.tie(nullptr);cout.tie(nullptr);
// #define int long long
#define all(v) v.begin(),v.end()
using namespace std;
mt19937 rnd(chrono::steady_clock::now().time_since_epoch().count());

const int N = 1e5 + 17, MX = 1e7 + 1, inf = 1e9, mod = 998244353;

int n, m;
vector<array<int, 3>> g[N];
int ans[N];

struct node{
    int ans, mn, mx, cnt;
};

node t[MX];
int add[MX], L[MX], R[MX], timer = 1;

node f(node a, node b){
    node res; 
    res.ans = a.ans + b.ans;
    if(a.mn < b.mn) res.mn = a.mn, res.cnt = a.cnt;
    else if(a.mn > b.mn) res.mn = b.mn, res.cnt = b.cnt;
    else res.mn = a.mn, res.cnt = a.cnt + b.cnt;
    res.mx = max(a.mx, b.mx);
    return res;
}

void push(int v, int tl, int tr){
    if(add[v] == 0) return;
    if(t[v].mx == 0 || t[v].cnt == 0) t[v].cnt = tr - tl + 1;
    if(add[v] < 0){
        if(t[v].mx + add[v] <= 0){
            t[v].mx = t[v].mn = t[v].ans = 0;
            t[v].cnt = tr - tl + 1;
        }
        else if(t[v].mn + add[v] > 0){
            t[v].mx += add[v];
            t[v].mn += add[v];
        }
    }
    else{
        if(t[v].mn == 0) t[v].ans += t[v].cnt;
        t[v].mn += add[v];
        t[v].mx += add[v];
    }
    if(tl < tr){
        add[L[v]] += add[v];
        add[R[v]] += add[v];
    }
    add[v] = 0;
}


void upd(int v, int tl, int tr, int l, int r, int x){
    if(!L[v]) L[v] = ++timer;
    if(!R[v]) R[v] = ++timer;
    push(v, tl, tr);
    if(tl > r || l > tr) return;
    if(tl >= l && r >= tr && (add[v] + x >= 0 || t[v].mn + add[v] + x > 0 || t[v].mx + add[v] + x <= 0)){
        add[v] += x;
        push(v, tl, tr);
        return;
    }
    int mid = (tl + tr) / 2;
    upd(L[v], tl, mid, l, r, x);
    upd(R[v], mid + 1, tr, l, r, x);
    if(!t[R[v]].cnt) t[R[v]].cnt = tr - mid;
    if(!t[L[v]].cnt) t[L[v]].cnt = mid - tl + 1;
    t[v] = f(t[L[v]], t[R[v]]);
}

void dfs(int v, int p){
    ans[v] = t[1].ans;
    for(auto [to, l, r] : g[v]){
        if(to == p) continue;
        upd(1, 1, m, l, r, 1);
        dfs(to, v);
        upd(1, 1, m, l, r, -1);
    }
}

void solve(){
    cin >> n >> m;
    for(int i = 1; i < n; i++){
        int a, b, l, r;
        cin >> a >> b >> l >> r;
        g[a].push_back({b, l, r});
        g[b].push_back({a, l, r});
    }
    dfs(1, 1);
    for(int i = 2; i <= n; i++){
        cout << ans[i] << '\n';
    }
}

signed main(){
    SS
    // freopen("trains.in", "r", stdin);
    // freopen("trains.out", "w", stdout);

    int t = 1;
    // cin >> t;
    while(t--){
        solve();
    }
}

• Subtask 1: 11 / 11
• Subtask 2: 13 / 13
• Subtask 3: 16 / 16
• Subtask 4: 29 / 29
• Subtask 5: 31 / 31