제출 #1308136

#제출 시각아이디문제언어결과실행 시간메모리
1308136WeIlIaNNafta (COI15_nafta)C++20
100 / 100
265 ms155888 KiB
#include <bits/stdc++.h> using namespace std; #define MOD1 1000000007 #define MOD2 998244353 #define fir first #define sec second #define pushf push_front #define pushb push_back #define popf pop_front #define popb pop_back #define mp make_pair #define all(a) a.begin(), a.end() #define lbound(v, x) lower_bound(all(v), x) - v.begin() #define ubound(v, x) upper_bound(all(v), x) - v.begin() #define chmax(a, b) a = max(a, b) #define chmin(a, b) a = min(a, b) #define FOR1(a) for (int _ = 0; _ < (a); ++_) #define FOR2(i, a) for (int i = 0; i < (a); ++i) #define FOR3(i, a, b) for (int i = (a); i < (b); ++i) #define RFOR1(a) for (int _ = (a)-1; _ >= 0; --_) #define RFOR2(i, a) for (int i = (a)-1; i >= 0; --i) #define RFOR3(i, a, b) for (int i = (b)-1; i >= (a); --i) #define overload3(a, b, c, d, ...) d // Always choose the fourth argument to call. Hence, which function to call is determined by the number of given arguments. #define REP(...) overload3(__VA_ARGS__, FOR3, FOR2, FOR1)(__VA_ARGS__) #define RREP(...) overload3(__VA_ARGS__, RFOR3, RFOR2, RFOR1)(__VA_ARGS__) typedef long long ll; typedef pair<int, int> pii; typedef vector<int> vi; typedef pair<ll, ll> pll; typedef vector<ll> vll; typedef vector<bool> vb; typedef vector<char> vc; typedef vector<string> vs; typedef vector<pii> vpii; typedef vector<pll> vpll; typedef vector<vi> vvi; typedef vector<vll> vvll; typedef vector<vb> vvb; typedef vector<vc> vvc; typedef vector<vpii> vvpii; typedef vector<vpll> vvpll; typedef queue<int> qi; typedef queue<ll> qll; typedef queue<pii> qpii; typedef queue<pll> qpll; typedef deque<int> dqi; typedef deque<ll> dqll; typedef deque<pii> dqpii; typedef deque<pll> dqpll; typedef priority_queue<int> pqi; typedef priority_queue<ll> pqll; typedef priority_queue<pii> pqpii; typedef priority_queue<pll> pqpll; typedef priority_queue<int, vi, greater<int> > r_pqi; typedef priority_queue<ll, vll, greater<ll> > r_pqll; typedef priority_queue<pii, vpii, greater<pii> > r_pqpii; typedef priority_queue<pll, vpll, greater<pll> > r_pqpll; const ll inf = 1e18; const int dir[5] = {-1, 0, 1, 0, -1}; ll sums[2010]; ll dp[2010][2010]; ll cost[2010][2010]; void compute(int g, int l, int r, int optL, int optR) { if (l > r) return; int mid = (l + r) / 2; ll best = 0; int bestOpt = -1; for (int k = optL; k <= min(mid - 1, optR); k++) { ll val = dp[g - 1][k] + cost[k + 1][mid]; if (val > best) { best = val; bestOpt = k; } } dp[g][mid] = best; compute(g, l, mid - 1, optL, bestOpt); compute(g, mid + 1, r, bestOpt, optR); } int main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); int n, m; cin>>n>>m; vvc grid(n+2, vc(m+2, '.')); REP(i, 1, n+1) { REP(j, 1, m+1) { cin>>grid[i][j]; } } int L, R, C; function<void(int, int)> dfs = [&](int x, int y) { chmin(L, y); chmax(R, y); C += (grid[x][y] - '0'); grid[x][y] = '.'; REP(i, 4) { int nx = x + dir[i], ny = y + dir[i+1]; if(grid[nx][ny] != '.') { dfs(nx, ny); } } }; vvpii arr(m+2); REP(i, 1, n+1) { REP(j, 1, m+1) { if(grid[i][j] != '.') { L = m+2, R = 0, C = 0; dfs(i, j); // cerr<<L<<' '<<R<<' '<<C<<endl; arr[L].pushb(mp(R, C)); } } } vll cnt(m+2, 0); for (int j = m; j >= 1; --j) { for (auto &p: arr[j]) REP(i, j, p.first+1) cnt[i] += p.second; REP(i, j, m+1) cost[j][i] = cnt[i]; } // REP(i, 1, m+1) { // REP(j, 1, m+1) { // cerr<<cost[i][j]<<' '; // } // cerr<<endl; // } ll ans = 0; REP(i, 1, m+1) { dp[1][i] = cost[1][i]; chmax(ans, dp[1][i]); } cout<<ans<<endl; REP(i, 2, m+1) { compute(i, 1, m, 1, m); ans = 0; REP(j, 1, m+1) { chmax(ans, dp[i][j]); } cout<<ans<<endl; } }
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