Submission #1306304

#	Time	Username	Problem	Language	Result	Execution time	Memory
1306304		thecrazycandy	Political Development (BOI17_politicaldevelopment)	C++20	16 / 100	594 ms	241220 KiB

politicaldevelopment

#include <bits/stdc++.h>
//#pragma GCC optimize("Ofast")
//#pragma GCC target("avx,avx2,fma")
using namespace std;
#define ll long long
#define sped_up ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define rall(v) (v).rbegin(), (v).rend()
#define all(v) (v).begin(), (v).end()
#define pb push_back
#define S second
#define F first
const ll INF = (ll)1e9 + 1, INFL = (ll)1e18 + 1;
const ll mod = (ll)1e9 + 7, MAXN = (ll)5e3 + 1;
vector <ll> g[MAXN];
bool c[MAXN][MAXN];
ll used[MAXN];
ll col = 0;
void dfs (ll v) {
    bool ok = 0;
    used[v] = 1;
    for (int i = 1; i <= col; i++) ok |= c[i][v];
    if (!ok) col++;
    for (int i = 1; i <= col; i++) {
        if (c[i][v]) for (auto j : g[v]) c[i][j] = 0;
    }
    for (auto i : g[v]) if (used[i] == 0) dfs(i);
    for (int i = 1; i <= col; i++) {
        if (c[i][v]) for (auto j : g[v]) c[i][j] = 0;
    }
}
int main() {
    sped_up;
    ll n, k;
    cin >> n >> k;
    ll ans = 0;
    for (int i = 1; i <= n; i++) {
        ll a;
        cin >> a;
        while (a--) {
            ll b;
            cin >> b;
            c[i][b + 1] = 1;
            c[b + 1][i] = 1;
        }
    }
    for (int i = 1; i <= n; i++) {
        for (int j = 1; j <= n; j++) {
            if (i != j && !c[i][j]) g[i].pb(j);
            c[i][j] = 1;
        }
    }
    for (int i = 1; i <= n; i++) {
        ll mx = 0;
        if (used[i] == 0) {
            dfs(i);
            for (int j = 1; j <= col; j++) {
                ll cnt = 0;
                for (int l = 1; l <= n; l++) {
                    if (used[l] == 1) cnt += c[j][l];
                    c[j][l] = 1;
                }
                mx = max(mx, cnt);
            }
            for (int j = 1; j <= n; j++) if (used[j] == 1) used[j] = 2;
            ans += mx;
            col = 0;
        }
    }
    cout << ans;
}

• Subtask 1: 4 / 4
• Subtask 2: 12 / 12
• Subtask 3: 0 / 23
• Subtask 4: 0 / 38
• Subtask 5: 0 / 23