이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define long long long
#define pii pair<long, long>
#define x first
#define y second
using namespace std;
const int N = 1e5+5;
vector<pii> g[N];
void sssp(int src, long d[]) {
fill_n(d, N, 1e18);
priority_queue<pii, vector<pii>, greater<pii> > Q;
Q.emplace(d[src] = 0, src);
while(!Q.empty()) {
pii now = Q.top(); Q.pop();
if(d[now.y] != now.x) continue;
long u, w; tie(w, u) = now;
for(pii v : g[u]) if(w + v.y < d[v.x])
Q.emplace(d[v.x] = w + v.y, v.x);
}
}
int n, m, s, t, u, v;
long ds[N], dt[N], du[N], dv[N];
long solve(int a, int b, long da[], long db[]) {
long dp[N], len = da[b];
bool vis[N]; memset(vis, 0, sizeof vis);
priority_queue<pii, vector<pii>, greater<pii> > Q;
for(int i = 1; i <= n; i++) dp[i] = du[i];
Q.emplace(0, a), vis[a] = true;
while(!Q.empty()) {
pii now = Q.top(); Q.pop();
if(now.x != da[now.y]) continue;
long u, w; tie(w, u) = now;
for(pii v : g[u]) if(w + v.y + db[v.x] == len) {
dp[v.x] = min(dp[v.x], dp[u]);
if(!vis[v.x]) vis[v.x] = true, Q.emplace(w + v.y, v.x);
}
}
long ret = 1e18;
for(int i = 1; i <= n; i++) if(da[i] + db[i] == len)
ret = min(ret, dp[i] + dv[i]);
return ret;
}
int main() {
scanf("%d %d %d %d %d %d", &n, &m, &s, &t, &u, &v);
for(int i = 1, a, b, c; i <= m; i++) {
scanf("%d %d %d", &a, &b, &c);
g[a].emplace_back(b, c);
g[b].emplace_back(a, c);
}
sssp(s, ds), sssp(t, dt);
sssp(u, du), sssp(v, dv);
printf("%lld\n", min({du[v], solve(s, t, ds, dt), solve(t, s, dt, ds)}));
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
commuter_pass.cpp: In function 'int main()':
commuter_pass.cpp:54:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
scanf("%d %d %d %d %d %d", &n, &m, &s, &t, &u, &v);
~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
commuter_pass.cpp:56:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
scanf("%d %d %d", &a, &b, &c);
~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
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