제출 #130152

#제출 시각아이디문제언어결과실행 시간메모리
130152mlyean00수열 (APIO14_sequence)C++14
100 / 100
1727 ms82336 KiB
#include <bits/stdc++.h> using namespace std; using ll = long long; struct line { int idx; ll a, b; line(int idx, ll a, ll b) : idx(idx), a(a), b(b) {} ll cost(ll x) const { return a * (x - a) + b; } ll intersect(line const& other) { if (a == other.a) return 1LL << 32; return ((other.a * other.a - other.b) - (a * a - b)) / (other.a - a); } }; int main() { int n, k; cin >> n >> k; vector<int> a(n); for (int i = 0; i < n; ++i) { cin >> a[i]; } vector<ll> pref(n + 1, 0); partial_sum(a.begin(), a.end(), pref.begin() + 1); vector<ll> dp1(n + 1, 0); int parent[k + 1][n + 1]; for (int i = 1; i <= k; ++i) { vector<ll> dp2(n + 1, 0); deque<line> dq; for (int j = 0; j <= n; ++j) { while (dq.size() > 1 && dq[0].cost(pref[j]) <= dq[1].cost(pref[j])) { dq.pop_front(); } if (!dq.empty()) { dp2[j] = dq[0].cost(pref[j]); parent[i][j] = dq[0].idx; } line l(j, pref[j], dp1[j]); while (dq.size() > 1) { int sz = dq.size(); ll t1 = dq[sz - 2].intersect(dq[sz - 1]); ll t2 = dq[sz - 1].intersect(l); if (t1 < t2) break; dq.pop_back(); } dq.push_back(l); } dp1 = move(dp2); } cout << dp1[n] << endl; int u = n; for (int i = k; i > 0; --i) { u = parent[i][u]; cout << u << ' '; } cout << endl; return 0; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...