Submission #1300443

#TimeUsernameProblemLanguageResultExecution timeMemory
1300443muhammad-mutahirExamination (JOI19_examination)C++20
20 / 100
125 ms19020 KiB
#include <bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/detail/standard_policies.hpp>
using namespace __gnu_pbds;

#define print(l) for(auto i:l) cout<<i<<" ";cout<<endl;
#define input(t,l,n) vector<t>l(n);for(int i = 0;i<n;i++)cin>>l[i];
#define int long long
#define pb push_back
#define all(l) l.begin(),l.end()
#define pii pair<int,int>
#define fi first
#define se second

typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update>ordered_set;
typedef tree<int,null_type,less_equal<int>,rb_tree_tag,tree_order_statistics_node_update>ordered_multiset;

const int M = 1e9+7;
const int inf = 1e18;


int bp(int x, int y, int p){
    int res = 1;
    x = x % p;
    while (y > 0) {
 
        if (y & 1)
            res = (res * x) % p;
        y = y >> 1;
        x = (x * x) % p;
    }
    return res;
}
 
int MI(int n, int p){
    return bp(n, p - 2, p);
}
int mul(int x,int y, int p){
    return x * 1ull * y % p;
}
int di(int x,int y, int p){
    return mul(x, MI(y, p), p);
}


int n , m , k , q;

void solve(int testcase_number){
    cin>>n>>q;
    int b = 1e9+1;
    vector<vector<int>>ord;
    for(int i = 0;i<n;i++){
    	int s,t;
    	cin>>s>>t;
    	ord.pb({s,t});
    }
    sort(all(ord));
    reverse(all(ord));
    vector<vector<int>>qur;
    for(int i =0 ;i<q;i++){
    	int x,y,z;
    	cin>>x>>y>>z;
    	qur.pb({x,y,i});
    }
    sort(all(qur));
    reverse(all(qur));

    // for(auto i:ord){
    	// print(i);
    // }
    // for(auto i:qur){
    	// print(i);
    // }
    // set<int>st = {1,2,3,4,5};
    // cout<<(st.lower_bound(3)-st.begin())<<endl;
    ordered_multiset ms;
    // multiset<int>ms;
    int p1 =0;
    int p2 =0 ;
    vector<int>ans(q);
    while(p1 < n and p2<q){
    	// cout<<qur[p2][0]<<" "<<qur[p2][1]<<" "<<qur[p2][2]<<endl;
    	while(p1<n and ord[p1][0] >= qur[p2][0]){
    		ms.insert(ord[p1][1]);
    		p1++;
    	}
    	// auto c = ms.lower_bound(qur[p2][1]);
    	ans[qur[p2][2]] = ms.size()-ms.order_of_key(qur[p2][1]);
    	p2++;
    }
    while(p2<q){
    	ans[qur[p2][2]] = ms.size()-ms.order_of_key(qur[p2][1]);
    	p2++;
    }
    print(ans);
    
    




}


signed main(){
    ios::sync_with_stdio(0);//DO NOT USE IN INTERACTIVE
    cin.tie(0), cout.tie(0);
    cout << fixed<<setprecision(9);

    int t = 1;
    // cin>>t;
    for(int i = 1;i<=t;i++){
        solve(i);
    }

}
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