이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/*DavitMarg*/
#include <iostream>
#include <algorithm>
#include <cmath>
#include <vector>
#include <string>
#include <cstring>
#include <map>
#include <set>
#include <queue>
#include <iomanip>
#include <stack>
#include <cassert>
#include <iterator>
#include <bitset>
#include <fstream>
#define mod 1000000007ll
#define LL long long
#define LD long double
#define MP make_pair
#define PB push_back
#define all(v) v.begin(),v.end()
using namespace std;
int n,st,en;
LL dp1[202][202][202],dp0[202][202][202],pr1[202][202][202],pr0[202][202][202];
int main()
{
cin>>n>>st>>en;
// if(st>en)
// swap(st,en);
dp1[2][1][2]=1;
dp0[2][2][1]=1;
dp1[2][1][2]=1;
dp0[2][2][1]=1;
for(int i=3;i<=n;i++)
{
for(int t=1;t<=i;t++)
for(int s=1;s<=i;s++)
{
pr0[i-1][s][t]=pr0[i-1][s-1][t]+dp0[i-1][s][t];
pr1[i-1][s][t]=pr1[i-1][s-1][t]+dp1[i-1][s][t];
}
for(int t=1;t<=i;t++)
{
for(int s=1;s<=i;s++)
{
if(s==t)
continue;
dp0[i][s][t]=pr1[i-1][s-1][t-(s<t)];
dp1[i][s][t]=(pr0[i-1][i][t-(s<t)]-pr0[i-1][s-1][t-(s<t)]+mod);
dp1[i][s][t]%=mod;
dp0[i][s][t]%=mod;
//cout<<"!!0 "<< i <<" "<< s <<" "<< t <<" = "<<dp0[i][s][t]<<endl;
//cout<<"!!1 "<< i <<" "<< s <<" "<< t <<" = "<<dp1[i][s][t]<<endl;
}
}
}
cout<<(dp0[n][st][en]+dp1[n][st][en])%mod<<endl;
return 0;
}
/*
*/
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