This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = pair<int, int>;
const int inf = 1e9;
const int maxn = 500005;
const int maxq = 500005;
struct Node {
int sum, msuf;
Node(int s, int m) : sum(s), msuf(m) {}
Node() : sum(0), msuf(0) {}
};
int n, q;
int a[maxn];
Node tree[4*maxn];
int answer[maxq];
int ql[maxq], qr[maxq];
vector<int> queries[maxn]; // query[i] = ids of queries such that L=i
void merge(Node& v, Node& l, Node& r) {
v.sum = l.sum + r.sum;
v.msuf = min(l.msuf + r.sum, r.msuf);
}
void build(int v, int tl, int tr) {
if (tl == tr) {
tree[v].sum = a[tl];
tree[v].msuf = min(0, a[tl]);
return;
}
int tm = (tl + tr) / 2;
build(2*v, tl, tm);
build(2*v+1, tm+1, tr);
merge(tree[v], tree[2*v], tree[2*v+1]);
}
void update(int v, int tl, int tr, int pos, int val) {
if (tl == tr) {
tree[v].sum = val;
tree[v].msuf = min(0, val);
return;
}
int tm = (tl + tr) / 2;
if (pos <= tm) {
update(2*v, tl, tm, pos, val);
} else {
update(2*v+1, tm+1, tr, pos, val);
}
merge(tree[v], tree[2*v], tree[2*v+1]);
}
Node query(int v, int tl, int tr, int l, int r) {
if (l > r) return Node(0, inf);
if (l <= tl && tr <= r) return tree[v];
int tm = (tl + tr) / 2;
Node res1 = query(2*v, tl, tm, l, min(r, tm));
Node res2 = query(2*v+1, tm+1, tr, max(l, tm+1), r);
res1.msuf += res2.sum;
return Node(res1.sum + res2.sum, min(res1.msuf, res2.msuf));
}
int main() {
ios::sync_with_stdio(false); cin.tie(0);
cin >> n;
for (int i = 1; i <= n; ++i) {
char ch;
cin >> ch;
a[i] = (ch == 'C') ? 1 : -1;
}
cin >> q;
for (int i = 1; i <= q; ++i) {
cin >> ql[i] >> qr[i];
queries[ql[i]].push_back(i);
}
build(1, 1, n);
vector<int> stk; // which positions should be removed (decreasing order)
for (int L = n; L >= 1; --L) {
if (a[L] == 1 && !stk.empty()) {
int i = stk.back();
stk.pop_back();
update(1, 1, n, i, a[i]); // original value
} else if (a[L] == -1) {
stk.push_back(L);
update(1, 1, n, L, 0); // set it to 0
}
for (int i : queries[L]) {
int R = qr[i];
auto it = upper_bound(stk.rbegin(), stk.rend() , R);
answer[i] = 0;
answer[i] += distance(stk.rbegin(), it); // which votes will be removed by pass from L to R
answer[i] += -query(1, 1, n, L, R).msuf; // which will be removed from R to L (assuming the previous pass was done)
}
}
for (int i = 1; i <= q; ++i) {
cout << answer[i] << '\n';
}
}
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