Submission #1298112

#TimeUsernameProblemLanguageResultExecution timeMemory
1298112BahaminSnake Escaping (JOI18_snake_escaping)C++20
22 / 100
2096 ms14168 KiB
#include <bits/stdc++.h> using namespace std; template<typename A, typename B> ostream& operator<<(ostream &os, const pair<A, B> &p) { return os << '(' << p.first << ", " << p.second << ')'; } template<typename T_container, typename T = typename enable_if<!is_same<T_container, string>::value, typename T_container::value_type>::type> ostream& operator<<(ostream &os, const T_container &v) { os << '{'; string sep; for (const T &x : v) os << sep << x, sep = ", "; return os << '}'; } #define ll long long #define ld long double #define all(a) (a).begin(), (a).end() #define sui cout.tie(NULL); cin.tie(NULL); ios_base::sync_with_stdio(false) const int MAX_N = 1e5 + 5; const int MOD = 1e9 + 7; const ll INF = 1e9; const ld EPS = 1e-9; const int LOG = -1; int sum[0]; void solve() { int n, q; cin >> n >> q; string s; cin >> s; int a[(1 << n)]; int dp[(1 << n)]; int dp2[(1 << n)]; for (int i = 0; i < (1 << n); i++) dp[i] = dp2[i] = a[i] = s[i] - '0'; for (int i = 0; i < n; i++) { for (int j = (1 << n) - 1; j >= 0; j--) if (j & (1 << i)) dp[j] += dp[j ^ (1 << i)]; for (int j = 0; j < (1 << n); j++) if (!(j & (1 << i))) dp2[j] += dp2[j ^ (1 << i)]; } while (q--) { string t; cin >> t; reverse(all(t)); vector<int> al; int sum1 = 0; int sum0 = 0; for (int i = 0; i < n; i++) { if (t[i] == '?') al.push_back(i); else if (t[i] == '1') sum1 += (1 << i); else sum0 += (1 << i); } if ((int) al.size() <= LOG) { int ans = a[sum1]; sum[0] = 0; for (int j = 1; j < (1 << al.size()); j++) { int ind = 31 - __builtin_clz(j); sum[j] = sum[j - (1 << ind)] ^ (1 << al[ind]); ans += a[sum[j] + sum1]; } cout << ans << "\n"; } else if (__builtin_popcount(sum1) <= LOG) { int num1 = 0; for (int x : al) num1 ^= (1 << x); int ans = 0; int num2 = sum1; while (num2) { ans += (__builtin_popcount(num2 ^ sum1) & 1 ? -1 : 1) * dp[num1 + num2]; num2 = (num2 - 1) & sum1; } ans += (__builtin_popcount(num2 ^ sum1) & 1 ? -1 : 1) * dp[num1 + num2]; cout << ans << "\n"; } else { int ans = 0; int num2 = sum0; while (num2) { ans += (__builtin_popcount(num2) & 1 ? -1 : 1) * dp2[num2 + sum1]; num2 = (num2 - 1) & sum0; } ans += (__builtin_popcount(num2) & 1 ? -1 : 1) * dp2[num2 + sum1]; cout << ans << "\n"; } } } int main() { sui; int tc = 1; //cin >> tc; for (int t = 1; t <= tc; t++) { solve(); } }
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