Submission #1298012

#TimeUsernameProblemLanguageResultExecution timeMemory
1298012WeIlIaNMonkey and Apple-trees (IZhO12_apple)C++20
100 / 100
491 ms205520 KiB
#include <bits/stdc++.h>
using namespace std;

#define MOD1 1000000007
#define MOD2 998244353
#define fir first
#define sec second

#define pushf push_front
#define pushb push_back
#define popf pop_front
#define popb pop_back
#define mp make_pair
#define all(a) a.begin(), a.end()
#define lbound(v, x) lower_bound(all(v), x) - v.begin()
#define ubound(v, x) upper_bound(all(v), x) - v.begin()
#define chmax(a, b) a = max(a, b)
#define chmin(a, b) a = min(a, b)

#define FOR1(a) for (int _ = 0; _ < (a); ++_)
#define FOR2(i, a) for (int i = 0; i < (a); ++i)
#define FOR3(i, a, b) for (int i = (a); i < (b); ++i)
#define RFOR1(a) for (int _ = (a)-1; _ >= 0; --_)
#define RFOR2(i, a) for (int i = (a)-1; i >= 0; --i)
#define RFOR3(i, a, b) for (int i = (b)-1; i >= (a); --i)
#define overload3(a, b, c, d, ...) d
// Always choose the fourth argument to call. Hence, which function to call is determined by the number of given arguments.
#define REP(...) overload3(__VA_ARGS__, FOR3, FOR2, FOR1)(__VA_ARGS__)
#define RREP(...) overload3(__VA_ARGS__, RFOR3, RFOR2, RFOR1)(__VA_ARGS__)

typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef pair<ll, ll> pll;
typedef vector<ll> vll;
typedef vector<bool> vb;
typedef vector<char> vc;
typedef vector<string> vs;
typedef vector<pii> vpii;
typedef vector<pll> vpll;
typedef vector<vi> vvi;
typedef vector<vll> vvll;
typedef vector<vb> vvb;
typedef vector<vc> vvc;
typedef vector<vpii> vvpii;
typedef vector<vpll> vvpll;
typedef queue<int> qi;
typedef queue<ll> qll;
typedef queue<pii> qpii;
typedef queue<pll> qpll;
typedef deque<int> dqi;
typedef deque<ll> dqll;
typedef deque<pii> dqpii;
typedef deque<pll> dqpll;
typedef priority_queue<int> pqi;
typedef priority_queue<ll> pqll;
typedef priority_queue<pii> pqpii;
typedef priority_queue<pll> pqpll;
typedef priority_queue<int, vi, greater<int> > r_pqi;
typedef priority_queue<ll, vll, greater<ll> > r_pqll;
typedef priority_queue<pii, vpii, greater<pii> > r_pqpii;
typedef priority_queue<pll, vpll, greater<pll> > r_pqpll;

struct node {
	node *left, *right;
	int s, e;
	ll val, lazy;
	node() {}
	node(int _s, int _e) : s(_s), e(_e) {
		left = right = nullptr;
		val = 0;
		lazy = 0;
	}
	void push() {
		if(s == e) {
			return;
		}
		// to support negative index
		int m = (s + e) / 2;
		if(left == nullptr) {
			left = new node(s, m);
			right = new node(m + 1, e);
		}
		if(lazy == 1) {
			left->val = (m - s + 1);
			left->lazy = 1;
			right->val = (e - m);
			right->lazy = 1;
			lazy = 0;
		}
	}
	void update(int l, int r) {
		if(l > e || s > r) {
			return;
		}
		if(l <= s && e <= r) {
			val = (e - s + 1);
			lazy = 1;
			return;
		}
		push();
		left->update(l, r);
		right->update(l, r);
		val = left->val + right->val;
	}
	ll query(int l, int r) { 
		if(l > e || s > r) {
			return 0;
		}
		if(l <= s && e <= r) {
			return val;
		}
		push();
		return left->query(l, r) + right->query(l, r);
	}
};

void solve() {
	int n;
	ll c = 0;
	cin>>n;
	node* root = new node(0, int(1e9 + 5));
	REP(i, n) {
		int op;
		cin>>op;
		int p, q;
		cin>>p>>q;
		p += c;
		q += c;
		if(op == 2) {
			root->update(p, q);
		}
		else {
			c = root->query(p, q);
			cout<<c<<endl;
		}
	}
}

int main() {
	ios::sync_with_stdio(0);
	cin.tie(0);
	cout.tie(0);
	int T;
	T = 1;
	while(T--) {
		solve();
	}
}

 
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