이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "minerals.h"
#include <vector>
using namespace std;
int l[43000], r[43000],m[43000];
int ans[43000];
void Solve(int N) {
int NN = N + N;
int last = 0;
vector<int> X,Y;
for (int i = 1; i <= NN; ++i) {
int in = Query(i);
if (in == last) {
int yix = Y.size();
l[yix] = 0, r[yix] = X.size() - 1;
Y.push_back(i);
}
else X.push_back(i);
last = in;
}
int dir = 1;
while (1) {
vector<int> v[43000];//ix li
int in = 0;
for (int i = 0; i < N; ++i) {
if (l[i] <= r[i]) {
m[i] = (l[i] + r[i]) >> 1;
v[m[i]].push_back(i);//yix
++in;
}
}
if (in == 0) break;
if (dir) {
for (int i = N - 1; i >= 0; --i) {
for (auto yix : v[i]) {
int y = Y[yix];
in = Query(y);
if (in == last) r[yix] = i - 1, ans[yix] = i;
else l[yix] = i + 1;
last = in;
}
last = Query(X[i]);
}
}
else {
for (int i = 0; i < N; ++i) {
last = Query(X[i]);
for (auto yix : v[i]) {
int y = Y[yix];
in = Query(y);
if (in == last) r[yix] = i - 1, ans[yix] = i;
else l[yix] = i + 1;
last = in;
}
}
}
dir = 1 - dir;
}
for (int i = 0; i < N; ++i)
Answer(X[ans[i]],Y[i]);
}
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