제출 #1296952

#제출 시각아이디문제언어결과실행 시간메모리
1296952dostsPeru (RMI20_peru)C++20
0 / 100
1098 ms49248 KiB
#include "peru.h" #include <bits/stdc++.h> #pragma GCC optimize("O3,unroll-loops") #pragma GCC target("avx2") #define int long long #define pii pair<int,int> #define vi vector<int> #define ff first #define ss second #define sp << " " << #define all(x) x.begin(),x.end() #define big(x) ((int)(x.size())) using namespace std; const int MOD = 1e9+7, LIM = 1e6+1, inf = 2e18; const int N = 1e5+1; int add(int x,int y) { if ((x + y) >= MOD) return x + y - MOD; return x + y; } int mult(int x,int y) { return (1LL * x * y) % MOD; } int expo(int x,int y) { if (!y) return 1; int e = expo(x, y >> 1); e = mult(e, e); if (y & 1) e = mult(e, x); return e; } signed solve(signed n, signed k, signed* v){ vi a(n+1); for (int i=1;i<=n;i++) a[i] = v[i-1]; vi dp(n+1,inf); dp[0] = 0; a[0] = inf; int mx = 0; for (int j=1;j<k;j++) { mx = max(mx,a[j]); dp[j] = min(dp[j],mx); } deque<int> stk; for (int i=0;i<=n;i++) { while (!stk.empty() && a[stk.back()] <= a[i]) { stk.pop_back(); } stk.push_back(i); while (stk.front() <= i-k) stk.pop_front(); for (int j = 0;j<big(stk);j++) { if (j && i >= k) dp[i] = min(dp[i],a[stk[j]]+dp[stk[j-1]]); else if (i >= k) dp[i] = min(dp[i],a[stk[j]]+dp[i-k]); } } int mlt = 1; int ans = 0; for (int i = n;i>=1;i--) { ans = add(ans,mult(dp[i],mlt)); mlt = mult(mlt,23); } return ans; }
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