| # | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
|---|---|---|---|---|---|---|---|
| 1294166 | notbraining | Commuter Pass (JOI18_commuter_pass) | C++20 | 0 ms | 0 KiB |
//#pragma GCC optimize ("O3")
#include<iostream>
#include<vector>
#include<set>
#include<map>
#include<iomanip>
#include <cassert>
#include<algorithm>
#include <cstring>
#include<unordered_set>
#include<queue>
#include <array>
#include<cmath>
#include<unordered_map>
#include<queue>
#include <list>
#include <bitset>
using namespace std;
typedef long long ll;
using namespace std;
vector<pair<ll, ll>> graph[100001];
ll du[100001], dv[100001], ds[100001], dp[2][100001], ans;
bool visited[100001];
void dijkstra1(ll start, ll arr[]) {
fill(visited, visited + 100001, false);
priority_queue<pair<ll, ll>> pq;
pq.push({0, start});
while(!pq.empty()) {
ll c, node;
tie(c, node) = pq.top();
pq.pop();
if(!visited[node]) {
arr[node] = -c;
visited[node] = true;
for(auto& i : graph[node]) pq.push({c - i.second, i.first});
}
}
}
void dijkstra2(ll start, ll end) {
fill(dp[0], dp[0] + 100001, LLONG_MAX / 2);
fill(dp[1], dp[1] + 100001, LLONG_MAX / 2);
fill(visited, visited + 100001, false);
priority_queue<pair<ll, pair<ll, ll>>> pq;
pq.push({0, {start, 0}});
dp[0][0] = dp[1][0] = LLONG_MAX / 2;
while(!pq.empty()) {
ll c, node, par;
pair<ll, ll> p;
tie(c, p) = pq.top();
tie(node, par) = p;
pq.pop();
if(!visited[node]) {
visited[node] = true;
ds[node] = -c;
dp[0][node] = min(du[node], dp[0][par]);
dp[1][node] = min(dv[node], dp[1][par]);
for(auto i : graph[node]) pq.push({c - i.second, {i.first, node}});
} else if(-c == ds[node]) {
if(min(du[node], dp[0][par]) + min(dv[node], dp[1][par]) <=
dp[0][node] + dp[1][node]) {
cout << node << " " << par << " " << dp[0][node] << " " << dp[1][node] << endl;
dp[0][node] = min(du[node], dp[0][par]);
dp[1][node] = min(dv[node], dp[1][par]);
// cout << node << " " << par << " " << dp[0][node] << " " << dp[1][node] << endl;
}
}
}
ans = min(ans, dp[0][end] + dp[1][end]);
}
int main() {
iostream::sync_with_stdio(false);
cin.tie(0);
ll n, m, s, t, u, v;
cin >> n >> m >> s >> t >> u >> v;
for(int i = 0; i < m; i++) {
ll a, b, c;
cin >> a >> b >> c;
graph[a].push_back({b, c});
graph[b].push_back({a, c});
}
dijkstra1(u, du);
dijkstra1(v, dv);
ans = du[v];
dijkstra2(s, t);
//dijkstra2(t, s);
cout << ans << '\n';
return 0;
}
