Submission #1293778

#	Time	Username	Problem	Language	Result	Execution time	Memory
1293778		xosqedemrufo	Paprike (COI18_paprike)	C++20	13 / 100	33 ms	17456 KiB

paprike

//Author RufatM
#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/detail/standard_policies.hpp>
using namespace __gnu_pbds;
using namespace std;
typedef long long ll;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef vector<int> vi;
typedef vector<vector<int>> vvi;
typedef vector<ll> vll;
typedef vector<bool> vb;
typedef vector<string> vs;
#define fastio ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define endl '\n'
#define pb push_back
#define pf push_front
#define eb emplace_back
#define ff first
#define ss second
#define all(x) begin(x),end(x)
#define rall(x) rbegin(x),rend(x)
#define mt19937_64 mt_rand(chrono::steady_clock::now().time_since_epoch().count())
#define ordered_set tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update>
const int MOD=1000000007;
const int INF=1000000007;
const ll LINF=4e18;
const int MAXN=100005;
ll n,k;
ll dp[MAXN+1];
vi g[MAXN+1];
ll ans;
ll dfs(int u,int p){
    vll children;
    for(int v:g[u]){
        if(v==p){
            continue;
        }
        ll sub = dfs(v,u);
        children.pb(sub);
    }
    ll sum = dp[u];
    sort(all(children),greater<ll>());
    for(ll sub:children){
        if(sum+sub<=k){
            sum+=sub;
        }
        else{
            ans++;
        }
    }
    return sum;
}
signed main(){
    fastio;
    #ifndef ONLINE_JUDGE
    //freopen("input.txt","r",stdin);
    //freopen("output.txt","w",stdout);
    #endif
    int t=1;
    //cin >> t;
    while(t--){
        cin >> n >> k;
        for(int i=1;i<=n;i++){
            cin >> dp[i];
        }
        for(int i=0;i<n-1;i++){
            int x,y;
            cin >> x >> y;
            g[x].pb(y);
            g[y].pb(x);
        }
        ans = 0;
        dfs(1,0);
        cout << ans << endl;
    }
}

• Subtask 1: 0 / 11
• Subtask 2: 13 / 13
• Subtask 3: 0 / 27
• Subtask 4: 0 / 49