Submission #1290542

#TimeUsernameProblemLanguageResultExecution timeMemory
1290542AMel0n수열 (APIO14_sequence)C++20
0 / 100
1 ms336 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; #define FOR(i,N) for(ll i = 0; i < N; i++) #define all(x) (x).begin(), (x).end() #define F first #define S second // APIO 14 Split The Sequence /* dp[k][m] = max score if we made k splits and the kth split was just before index m dp[k][m] = max of: dp[k-1][i] + (ps[m-1]-p[i-1]) * (ps[N-1]-p[m-1]) for all (0 <= i < m) nxt[k][m] = i where i was the optimal preceeding split point for split point m */ const ll INF = 1e18; const ll MAXN = 1e5 + 5; const ll MAXK = 205; ll N, K, PS[MAXN], dp[MAXK][MAXN], nxt[MAXK][MAXN]; void solve(ll l, ll r, ll lOpt, ll rOpt, ll k) { if (l > r) return ; ll m = (l + r) / 2; pair<ll,ll> bsf = {-INF, -1}; for(ll i = lOpt; i <= min(m-1, rOpt); i++) { ll bruh = dp[k-1][i] + (PS[m-1] - PS[i-1]) * (PS[N-1] - PS[m-1]); bsf = max(bsf, {bruh, i}); } nxt[k][m] = bsf.S; dp[k][m] = bsf.F; // cout << l << ' ' << r << ' ' << lOpt << ' ' << rOpt << ' ' << k << ' ' << dp[k][m] << ' ' << dp[k-1][nxt[k][m]] << ' ' << nxt[k][m] << endl; solve(l, m-1, lOpt, bsf.S, k); solve(m+1, r, bsf.S, rOpt, k); } signed main() { cin.tie(0); ios::sync_with_stdio(false); cin >> N >> K; FOR(i, N) { cin >> PS[i]; if (i) PS[i] += PS[i-1]; } for(ll k = 1; k <= K; k++) solve(0, N-1, 0, N-1, k); ll bsf = -INF; ll idx = -1; FOR(i, N) { if (bsf < dp[K][i]) { bsf = dp[K][i]; idx = i; } } cout << bsf << endl << idx+1 << ' '; for(ll k = K-1; k > 0; k--) { cout << nxt[k][idx]+1 << ' '; idx = nxt[k][idx]; } }
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