제출 #1288446

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1288446		blackscreen1	게임 (IOI14_game)	C++20	100 / 100	251 ms	24720 KiB

game

#include "game.h"
#include <bits//stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef tree<long long, null_type, less<long long>, rb_tree_tag,
             tree_order_statistics_node_update>
    ordered_set;
typedef tree<long long, null_type, less_equal<long long>, rb_tree_tag,
             tree_order_statistics_node_update>
    ordered_multiset;
#define ll long long
#define ld long double
#define iloop(m, h) for (auto i = m; i != h; i += (m < h ? 1 : -1))
#define jloop(m, h) for (auto j = m; j != h; j += (m < h ? 1 : -1))
#define kloop(m, h) for (auto k = m; k != h; k += (m < h ? 1 : -1))
#define lloop(m, h) for (auto l = m; l != h; l += (m < h ? 1 : -1))
#define iloop_(m, h, g) for (auto i = m; i < h; i += g)
#define jloop_(m, h, g) for (auto j = m; j < h; j += g)
#define kloop_(m, h, g) for (auto k = m; k < h; k += g)
#define lloop_(m, h, g) for (auto l = m; l < h; l += g)
#define getchar_unlocked _getchar_nolock // comment before submission
#define pll pair<ll, ll>
#define plll pair<ll, pll>
#define pllll pair<pll, pll>
#define vll vector<ll>
#define qll queue<ll>
#define dll deque<ll>
#define pqll priority_queue<ll>
#define gll greater<ll>
#define INF 1000000000000000
#define MOD1 1000000007
#define MOD2 998244353
#define MOD3 1000000009
mt19937 rng(chrono::system_clock::now().time_since_epoch().count());
ll par[1505], conn[1505][1505], sz[1505], N;

ll find(ll x) {
	return (par[x] == x ? x : par[x] = find(par[x]));
}

void merge(ll x, ll y) {
	if (sz[x] < sz[y]) swap(x, y);
	par[y] = x;
	sz[x] += sz[y];
	iloop(0, N) if (find(i) == i && find(i) != x) conn[i][x] += conn[i][y], conn[x][i] += conn[y][i];
}

void initialize(int n) {
	N = n;
	iloop(0, n) par[i] = i, sz[i] = 1;
}

int hasEdge(int u, int v) {
    if (find(u) == find(v)) return 1;
    u = find(u), v = find(v);
    if (conn[u][v] != sz[u] * sz[v] - 1) {
		conn[u][v]++;
		conn[v][u]++;
		return 0;
	}
    merge(u, v);
    return 1;
}

• Subtask 1: 15 / 15
• Subtask 2: 27 / 27
• Subtask 3: 58 / 58