제출 #128618

#제출 시각아이디문제언어결과실행 시간메모리
128618UtahaAbduction 2 (JOI17_abduction2)C++14
27 / 100
369 ms63868 KiB
/*input 4 5 6 30 10 40 20 15 55 25 35 45 1 3 4 3 2 2 4 1 2 5 3 3 */ #include <bits/stdc++.h> #pragma GCC optimize("unroll-loops,no-stack-protector") using namespace std; typedef long long ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; typedef pair<ld,ld> pdd; #define IOS ios_base::sync_with_stdio(0); cin.tie(0) #define ALL(a) a.begin(),a.end() #define SZ(a) ((int)a.size()) #define F first #define S second #define REP(i,n) for(int i=0;i<((int)n);i++) #define pb emplace_back #define MP(a,b) make_pair(a,b) #define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end())))) #define GET_POS(c,x) (lower_bound(c.begin(),c.end(),x)-c.begin()) template<typename T1,typename T2> ostream& operator<<(ostream& out,pair<T1,T2> P){ out<<'('<<P.F<<','<<P.S<<')'; return out; } //}}} const ll maxn=2005; const ll maxlg=__lg(maxn)+2; const ll INF64=8000000000000000000LL; const int INF=0x3f3f3f3f; const ll MOD=ll(1e9+7); const ld PI=acos(-1); const ld eps=1e-9; //const ll p=880301; //const ll P=31; ll mypow(ll a,ll b){ ll res=1LL; while(b){ if(b&1) res=res*a%MOD; a=a*a%MOD; b>>=1; } return res; } pii operator+(pii A,pii B){return MP(A.F+B.F,A.S+B.S);} const pii dir[]={{0,1},{-1,0},{0,-1},{1,0}}; int n,m; int r[maxn],c[maxn]; int dp[4][maxn][maxn]; int go(int idx,int x,int y){ if(dp[idx][x][y]!=-1) return dp[idx][x][y]; int destX=x+dir[idx].F; int destY=y+dir[idx].S; if(destX<0||destX>=n||destY<0||destY>=m) return dp[idx][x][y]=0; if(idx&1){ // x movement; if(c[y]>r[destX]) return dp[idx][x][y]=go(idx,destX,destY)+1; else{ return dp[idx][x][y]=max(go(0,destX,destY),go(2,destX,destY))+1; } } else{ if(r[x]>c[destY]) return dp[idx][x][y]=go(idx,destX,destY)+1; else{ return dp[idx][x][y]=max(go(1,destX,destY),go(3,destX,destY))+1; } } } int main(){ IOS; int q; cin>>n>>m>>q; REP(i,n) cin>>r[i]; REP(i,m) cin>>c[i]; REP(i,4) REP(j,n) REP(k,m){ dp[i][j][k]=-1; } REP(i,4) REP(j,n) REP(k,m){ if(dp[i][j][k]==-1) go(i,j,k); } while(q--){ int x,y; cin>>x>>y; x--;y--; int ans=0; REP(i,4) ans=max(ans,dp[i][x][y]); cout<<ans<<'\n'; } return 0; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...