Submission #128538

#TimeUsernameProblemLanguageResultExecution timeMemory
128538qkxwsmExhibition (JOI19_ho_t2)C++14
100 / 100
80 ms5416 KiB
//reading is hard #include <bits/stdc++.h> using namespace std; template<class T, class U> void ckmin(T &a, U b) { if (a > b) a = b; } template<class T, class U> void ckmax(T &a, U b) { if (a < b) a = b; } #define MP make_pair #define PB push_back #define LB lower_bound #define UB upper_bound #define fi first #define se second #define FOR(i, a, b) for (auto i = (a); i < (b); i++) #define FORD(i, a, b) for (auto i = (a) - 1; i >= (b); i--) #define SZ(x) ((int) ((x).size())) #define ALL(x) (x).begin(), (x).end() #define INF 1000000007 #define LLINF 2696969696969696969ll #define MAXN 100013 typedef long long ll; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; typedef vector<int> vi; typedef vector<ll> vl; typedef vector<pii> vpi; typedef vector<pll> vpl; int N, M; pii arr[MAXN]; int lim[MAXN]; vi dp; bool check(int x) { //you need smth 0...x - 1 vi nums; FOR(i, 0, x) { nums.PB(lim[M - 1 - i]); } reverse(ALL(nums)); // for (int x : nums) // { // cerr << x << ' '; // } // cerr << endl; int iter = 0; FOR(i, 0, x) { while(iter < N && arr[iter].se > nums[i]) iter++; iter++; } return (iter <= N); } int32_t main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> N >> M; FOR(i, 0, N) { cin >> arr[i].se >> arr[i].fi; } sort(arr, arr + N); FOR(i, 0, M) { cin >> lim[i]; } sort(lim, lim + M); int lo = 0, hi = min(N, M); while(hi > lo) { int mid = (hi + lo + 1) >> 1; if (check(mid)) lo = mid; else hi = mid - 1; } cout << lo << '\n'; }
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