제출 #1284649

#제출 시각아이디문제언어결과실행 시간메모리
1284649adscoding사다리꼴 (balkan11_trapezoid)C++20
100 / 100
111 ms58656 KiB
#include <bits/stdc++.h> #define all(x) x.begin(), x.end() #define BIT(mask, x) ((mask >> (x)) & 1) #define FOR(i, a, b) for (int i = a, _b = b; i <= _b; ++i) #define FORD(i, a, b) for (int i = a, _b = b; i >= _b; --i) using namespace std; typedef long long ll; typedef unsigned long long ull; typedef pair<int, int> pii; typedef pair<ll, ll> pll; /*********************************** CON CUA BO HCN ***********************************/ const int maxn = 1e5 + 3, MOD = 30013; int n; struct Tra { int x, y, u, v; }; Tra a[maxn]; pii dp[maxn]; vector<int> ids; // Seg: max & cnt struct Node { int l, r, mx, cnt; Node() {l = r = mx = cnt = 0;} }; Node seg[maxn * 35]; int curNode; Node combine(Node x, Node y) { Node res; if (x.mx < y.mx) swap(x, y); res.mx = x.mx; res.cnt = x.cnt; if (x.mx == y.mx) (res.cnt += y.cnt) %= MOD; return res; } void upd(int id, int l, int r, int pos, pii val) { if (l == r) { if (seg[id].mx < val.first) seg[id].mx = val.first, seg[id].cnt = val.second; else if (seg[id].mx == val.first) (seg[id].cnt += val.second) %= MOD; return; } int mid = l + r >> 1; if (pos <= mid) { seg[++curNode] = seg[seg[id].l]; seg[id].l = curNode; upd(curNode, l, mid, pos, val); } else { seg[++curNode] = seg[seg[id].r]; seg[id].r = curNode; upd(curNode, mid + 1, r, pos, val); } int tmpl = seg[id].l, tmpr = seg[id].r; seg[id] = combine(seg[seg[id].l], seg[seg[id].r]); seg[id].l = tmpl; seg[id].r = tmpr; } Node get(int id, int l, int r, int u, int v) { if (l > v || r < u) return Node(); if (l >= u && r <= v) { return seg[id]; } int mid = l + r >> 1; return combine(get(seg[id].l, l, mid, u, v), get(seg[id].r, mid + 1, r, u, v)); } int root[maxn]; void solve() { cin >> n; FOR(i, 1, n) { cin >> a[i].x >> a[i].y >> a[i].u >> a[i].v; ids.push_back(a[i].v); } ids.push_back(-1e9); sort(all(ids)); ids.erase(unique(all(ids)), ids.end()); sort(a + 1, a + n + 1, [&](const Tra &x, const Tra &y) { return x.y < y.y; }); vector<int> Y(n + 1); FOR(i, 1, n) { Y[i] = a[i].y; a[i].v = lower_bound(all(ids), a[i].v) - ids.begin(); } int m = (int)ids.size() - 1; pii res = {0, 0}; root[0] = ++curNode; upd(root[0], 0, m, 0, {0, 1}); FOR(i, 1, n) { root[i] = ++curNode; seg[root[i]] = seg[root[i - 1]]; int pos = lower_bound(Y.begin(), Y.begin() + i, a[i].x) - Y.begin() - 1, it = lower_bound(all(ids), a[i].u) - ids.begin() - 1; dp[i] = {1, 1}; if (it > 0) { Node cur = get(root[pos], 0, m, 0, it); dp[i] = make_pair(cur.mx + 1, cur.cnt); } if (res.first < dp[i].first) res.first = dp[i].first, res.second = dp[i].second; else if (res.first == dp[i].first) (res.second += dp[i].second) %= MOD; upd(root[i], 0, m, a[i].v, dp[i]); } cout << res.first << ' ' << res.second << '\n'; } signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); #define TASK "TEST" if (fopen(TASK".INP", "r")) { freopen(TASK".INP", "r", stdin); freopen(TASK".OUT", "w", stdout); } solve(); return 0; } /* NOTES: Ta có thể lấy hai thằng (x1 --> x2, y1 --> y2) và (u1 --> u2, v1 --> v2) khi và chỉ khi u1 > x2 && v1 > y2 seg[id][x]: so thang tai vi tri id sort theo x2 tăng dần Sort base on u */

컴파일 시 표준 에러 (stderr) 메시지

trapezoid.cpp: In function 'int main()':
trapezoid.cpp:155:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  155 |         freopen(TASK".INP", "r", stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
trapezoid.cpp:156:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  156 |         freopen(TASK".OUT", "w", stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
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