Submission #1284341

#	Time	Username	Problem	Language	Result	Execution time	Memory
1284341		WH8	Dango Maker (JOI18_dango_maker)	C++20	13 / 100	2 ms	584 KiB

dango_maker

#include <bits/stdc++.h>
using namespace std;
#define int long long 
#define pll pair<int, int>
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define endl '\n'
#define ld long double
vector<tuple<int,int,int>> hd={{-1,1,1},{0,2,0},{1,1,1},{1,-1,1},{0,-2,0},{-1,-1,1}},
						vd={{-2,0,1},{-1,1,0},{1,1,0},{2,0,1},{1,-1,0},{-1,-1,0}};
signed main(){
	int h,w;cin>>h>>w;
	vector<vector<int>> m(h+2, vector<int>(w+2, 1));
	for(int i=1;i<=h;i++){
		for(int j=1;j<=w;j++){
			char c;cin>>c;
			if(c=='R')m[i][j]=0;
			else if(c=='G')m[i][j]=1;
			else m[i][j]=2;
		}
	}
	vector<vector<array<int, 2>>> v(h+2, vector<array<int,2>>(w+2, array<int,2>{0, 0}));
	vector<vector<int>> al(h*w);
	int nw=1;
	for(int i=1;i<=h;i++){
		for(int j=1;j<=w;j++){
			if(m[i][j]!=1)continue;
			bool hori=false;
			if((m[i][j-1]==0 and m[i][j+1]==2)){
				for (auto [dx,dy,t]:hd){
					int nx=i+dx, ny=j+dy;
					if(nx<=0 or nx>h or ny<=0 or ny>w or !v[nx][ny][t])continue;
					al[nw].pb(v[nx][ny][t]);
					al[v[nx][ny][t]].pb(nw);

				}
				v[i][j][0]=nw;
				hori=true;
				nw++;
				//~ printf("%lld %lld, hori\n",i,j);
			}
			if((m[i-1][j]==0 and m[i+1][j]==2)){
				for (auto [dx,dy,t]:vd){
					int nx=i+dx, ny=j+dy;
					if(nx<=0 or nx>h or ny<=0 or ny>w or !v[nx][ny][t])continue;
					al[nw].pb(v[nx][ny][t]);
					al[v[nx][ny][t]].pb(nw);

				}
				v[i][j][1]=nw;
				if(hori) {
					al[nw].pb(nw-1);
					al[nw-1].pb(nw);
				}
				nw++;
				//~ printf("%lld %lld, vert\n",i,j);
			}
		}
	}
	vector<int> clr(nw+5, -1);
	array<int,2> sm={0,0};
	auto dfs=[&](auto && dfs, int x, int p)->void{
		sm[p]++;
		for(auto it:al[x]){
			//~ printf("at %lld, going to %lld\n", x, it);
			if(clr[it]!=-1) {
				assert(clr[it]!=clr[x]);
				continue;
			}
			clr[it]=!p;
			dfs(dfs, it, !p);
		}
	};
	int ans=0;
	for(int i=1;i<nw;i++){
		if(clr[i]==-1){
			sm[0]=sm[1]=0;
			clr[i]=0;
			dfs(dfs, i, 0);
			ans+=max(sm[0], sm[1]);
		}
	}
	cout<<ans;
}

• Subtask 1: 13 / 13
• Subtask 2: 0 / 20
• Subtask 3: 0 / 67