제출 #1281044

#제출 시각아이디문제언어결과실행 시간메모리
1281044RufatBubble Sort Machine (JOI25_bubble)C++20
0 / 100
2094 ms31636 KiB
//Author RufatM #pragma GCC optimize("Ofast") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/detail/standard_policies.hpp> using namespace __gnu_pbds; using namespace std; typedef long long ll; typedef pair<int,int> pii; typedef pair<ll,ll> pll; typedef vector<int> vi; typedef vector<vector<int>> vvi; typedef vector<ll> vll; typedef vector<pii> vpii; typedef vector<vector<pii>> vvp; typedef vector<bool> vb; typedef vector<string> vs; #define fastio ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0); #define endl '\n' #define pb push_back #define pf push_front #define eb emplace_back #define ff first #define ss second #define all(x) begin(x),end(x) #define rall(x) rbegin(x),rend(x) #define mt19937_64 mt_rand(chrono::steady_clock::now().time_since_epoch().count()) #define ordered_set tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> template<typename T> bool isPrime(T n){if(n<=1)return false;if(n<=3)return true;if(n%2==0 or n%3==0)return false;for(T i=5;i*i<=n;i+=6)if(n%i==0 or n%(i+2)==0)return false;return true;} const int MOD=1000000007; const int INF=1000000007; const ll LINF=1e18+7; const int LOG=21; const int MAXN=100005; const int MAXM=200005; signed main(){ fastio; #ifndef ONLINE_JUDGE //freopen("input.txt","r",stdin); //freopen("output.txt","w",stdout); #endif int t=1; //cin >> t; while(t--){ int n; cin >> n; vll a(n+2),pref(n+2); for(int i=1;i<=n;i++){ cin >> a[i]; } set<int> st; for(int i=1;i<n;i++){ if(a[i]>a[i+1]){ st.insert(i); } } auto prefix_sum=[&](){ pref[0]=0; for(int i=1;i<=n;i++){ pref[i]=pref[i-1]+a[i]; } }; prefix_sum(); int q; cin >> q; while(q--){ int type; cin >> type; if(type==1){ vector<int> cur(all(st)); st.clear(); for(int i:cur){ if(a[i]>a[i+1]){ swap(a[i],a[i+1]); } } for(int i:cur){ for(int j=max(1,i-1);j<=min(n-1,i+1);j++){ if(a[j]>a[j+1]){ st.insert(j); } } } prefix_sum(); } else{ int l,r; cin >> l >> r; cout << pref[r]-pref[l-1] << endl; } } } }
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