Submission #1281014

#TimeUsernameProblemLanguageResultExecution timeMemory
1281014FaggiBit Shift Registers (IOI21_registers)C++20
54 / 100
2 ms872 KiB
#include <bits/stdc++.h> #define ll int #define sz(x) int(x.size()) #define forn(i, n) for (i = 0; i < n; i++) #define all(x) x.begin(), x.end() #define pb push_back #define mp make_pair #define fr first #define se second using namespace std; void append_move(int t, int x); void append_store(int t, std::vector<bool> v); void append_and(int t, int x, int y); void append_or(int t, int x, int y); void append_xor(int t, int x, int y); void append_not(int t, int x); void append_left(int t, int x, int s); void append_right(int t, int x, int s); void append_add(int t, int x, int y); void append_print(int t); void construct_instructions(int s, int n, int k, int q); void todo(ll &k) { append_and(1,0,99); // solo pares append_right(2,0,k); append_and(2,2,99); // solo impares append_xor(3,2,99); // impares negados append_add(3,3,1); // sumar -impares+pares append_right(3,3,k); append_add(3,3,99); // quedan k unos si n1<n2 o k ceros si n1>n2 append_and(4,3,1); // solo los pares que son < a n2 append_not(3,3); // quedan k unos si n1>n2 o k ceros si n1<n2 append_and(5,2,3); // solo los impares que son < n1 append_or(6,5,4); // union de pares e impares < append_xor(1,4,1); // solo pares que son > n2 append_left(1,1,k); // moverlos a la posicion correspondiente append_xor(2,2,5); // solo impares que son > n1 append_left(2,2,k); // moverlos a la posicion correspondiente append_or(7,2,1); // unir pares e impares > append_or(0,7,6); // unir ambos vectores } void construct_instructions(int s, int n, int k, int q) { ll i, b=2000, j; vector<bool>v(b,0); for(j=0; j<n; j+=2) for(i=0; i<k; i++) v[i+j*k]=1; append_store(99,v); if(n%2!=0) { vector<bool>v2(b,0); for(i=0; i<k; i++) v2[i+n*k]=1; append_store(97,v2); append_or(0,0,97); n++; } for(i=0; i<50; i++) { todo(k); // ordenar de a pares i e i+1 append_move(98,0); append_left(0,0,b-k*(n-1)); // borrar el ultimo numero append_right(0,0,b-k*(n-2)); // borrar el primer numero todo(k); // ordenar de a pares i e i+1 append_left(0,0,k); // dejar lugar para el primer numero append_left(96,98,b-k); // borrar todos los numeros menos el primero append_right(96,96,b-k); // acomodar el primer numero append_or(0,0,96); // agregarlo a 0 append_right(96,98,k*(n-1)); // borrar todos los numeros menos el ultimo append_left(96,96,k*(n-1)); // acomodar el ultimo numero append_or(0,0,96); // agregarlo a 0 } }
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