Submission #128023

#	Time	Username	Problem	Language	Result	Execution time	Memory
128023		RockyB	Worst Reporter 3 (JOI18_worst_reporter3)	C++17	19 / 100	2060 ms	85808 KiB

worst_reporter3

#include <bits/stdc++.h>

#define int ll

#define f first
#define s second

#define pb push_back
#define pp pop_back

#define all(x) x.begin(), x.end()
#define sz(x) (int)x.size()

#define rep(a, b, c) for (int a = (b); (a) <= (c); ++a)
#define per(a, b, c) for (int a = (b); (a) >= (c); --a) 

#define nl '\n'
#define ioi exit(0);

using namespace std;

typedef long long ll;

const int MAX_N = (int)5e5 + 7;

int n, q;
int d[MAX_N], l[MAX_N], r[MAX_N], t[MAX_N], ans[MAX_N];

map <int, vector <int> > off;

struct fenwick {
  pair <ll, int> f[MAX_N];

  void upd(int p, ll df, int t) {
    for (; p < MAX_N; p |= p + 1) {
      f[p].f += df;
      f[p].s += t;
    }
  }
  pair <ll, int> get(int p) {
    pair <ll, int> res = {0, 0};
    for (; p >= 0; p = (p & (p + 1)) - 1) {
      res.f += f[p].f;
      res.s += f[p].s;
    }
    return res;
  }
} F; 

pair <int, int> inter(pair <int, int> x, pair <int, int> y) {
  return {max(x.f, y.f), min(x.s, y.s)};
}
ll get_val(int p, int T) {
  pair <ll, int> cur = F.get(p);
  //cerr << cur.f << ' ' << T << nl;
  int one = p - cur.s; 
/*   if (S != -1) {
    pair <int, int> rng = inter({1, p}, {S, E});
    if (rng.f <= rng.s) {
      // cerr << cur.f << ' ' << one << nl;
      one -= pref[rng.s].s - pref[rng.f - 1].s;
      cur.f += pref[rng.s].f - pref[rng.f - 1].f;
    }
  }
 */
  return T - (cur.f + one);
}

int nxt[MAX_N], lst[MAX_N];
void prep() {
  int last = 1;
  rep(i, 1, n) {
    int df = (d[i] + last - 1) / last;
    lst[i] = df * last;
    last *= df;
  }
  per(i, n, 1) {
    if (lst[i] != lst[i + 1] || i == n) nxt[i] = i + 1;
    else nxt[i] = nxt[i + 1];
  }
}
void solve(int T, vector <int> &qr) {
  int add = T;
  vector < pair <int, ll > > del;
  int last = 1;
  /* rep(i, 1, n) cerr << lst[i] << ' ';
  cerr << nl; */
  for (int i = 1; i <= n && add; i = nxt[i]) {
    int df = (d[i] + last - 1) / last;

    if (!df) ioi
    del.pb({i, 1 + last * (add % df)});
    F.upd(i, 1 + last * (add % df), 1);   
    //cerr << 1 + last * (add % df) << ' ' << i << nl;
    //sum += 1 + last * (add % df);

    last *= df;
    add /= df;
  }
  /* last = 1;
  cerr << nl;
  add = T;
  for (int i = 1; i <= n; i++) {
    int df = (d[i] + last - 1) / last;
    cerr << 1 + last * (add % df) << ' ' << i << ' ' << last * df << nl;
    //sum += 1 + last * (add % df);

    last *= df;
    add /= df;
  } */


  for (auto it : qr) {
    int L = 0, R = n + 1;
    int lo = 1, hi = n;
    while (lo <= hi) {
      int mid = lo + hi >> 1;
      if (get_val(mid, T) >= l[it]) L = mid, lo = mid + 1;
      else hi = mid - 1;
    }
    lo = 1, hi = n;
    while (lo <= hi) {
      int mid = lo + hi >> 1;
      if (get_val(mid, T) <= r[it]) R = mid, hi = mid - 1;
      else lo = mid + 1;
    }
    //cerr << R << ' ' << L << nl;
    if (R <= L) ans[it] += L - R + 1;
    if (l[it] <= T && T <= r[it]) ans[it]++;

    //cerr << ans[it] << nl; 
    //ans[it] = upper_bound(all(a), r[it]) - lower_bound(all(a), l[it]);
  }

  // cout << ans[2] << nl;
  for (auto it : del) {
    F.upd(it.f, -it.s, -1);
  }
}
int32_t main() {
  #ifdef IOI
    freopen ("in.txt", "r", stdin);
    freopen ("C.out", "w", stdout);
  #endif
  ios_base :: sync_with_stdio(0), cin.tie(0), cout.tie(0);
  cin >> n >> q;
  d[0] = 1;
  rep(i, 1, n) {
    cin >> d[i];
  }
  rep(i, 1, q) {
    cin >> t[i] >> l[i] >> r[i];
    off[t[i]].pb(i);
  }
  prep();
  /* solve(4, off[4]);
  ioi */
  for (auto it : off) {
    solve(it.f, it.s);  
  }

  rep(i, 1, q) {
    cout << ans[i] << nl;
  }

  ioi
}

Compilation message (stderr)

worst_reporter3.cpp: In function 'void solve(ll, std::vector<long long int>&)':
worst_reporter3.cpp:117:20: warning: suggest parentheses around '+' inside '>>' [-Wparentheses]
       int mid = lo + hi >> 1;
                 ~~~^~~~
worst_reporter3.cpp:123:20: warning: suggest parentheses around '+' inside '>>' [-Wparentheses]
       int mid = lo + hi >> 1;
                 ~~~^~~~

• Subtask 1: 7 / 7
• Subtask 2: 12 / 12
• Subtask 3: 0 / 81