제출 #1278908

#제출 시각아이디문제언어결과실행 시간메모리
1278908iamsazidhArranging Shoes (IOI19_shoes)C++20
100 / 100
93 ms36412 KiB
//ᴇᴀᴄʜ ᴘᴇʀꜱᴏɴ ᴡɪʟʟ ᴏɴʟʏ ʜᴀᴠᴇ ᴡʜᴀᴛ ᴛʜᴇʏ ᴇɴᴅᴇᴀᴠᴏᴜʀᴇᴅ ᴛᴏᴡᴀʀᴅꜱ [53:39] //Author: Sazid Hasan #include <bits/stdc++.h> #include "shoes.h" using namespace std; typedef long long ll; typedef double dl; typedef vector<int> vi; typedef vector<vector<int>> vii; typedef vector<ll> vl; typedef vector<bool> vb; typedef pair<int,int> pii; typedef pair<ll, ll> pll; #define ff first #define ss second #define all(a) a.begin(),a.end() #define gcd(a,b) __gcd(a,b) #define lcm(a,b) (a*(b/gcd(a,b))) #define file(); freopen("input.txt", "r", stdin);freopen("output.txt", "w", stdout); #define flush fflush(stdout); #define spc " " #ifdef ONLINE_JUDGE #define debarr(array) #define deb(x) #define del #define debug(...) #else #define debarr(array) for(int w = 0; w < array.size(); w++) cerr << #array << "-" << w << " = " << array[w] << endl; #define deb(x) cerr << #x << " = " << x << endl; #define del cerr << '\n'; #endif const double PI = acos(-1); const int MOD = 1000000007; const int inf = (2147483647); const double EPS = 1e-6; const int MAXN = 1e5+10; class BIT{ private: vector<int> tr; int n; public: int lsb(int x){ return (x & -x); } BIT(int _n){ n = _n; tr.resize(n+1, 1); //all are 1 s first for(int i = 1; i <= n; i++){ if(i+lsb(i)<=n) tr[i+lsb(i)] += tr[i]; } } int till(int x){ int ans = 0; while(x>0){ ans += tr[x]; x -= lsb(x); } return ans; } int ask(int l, int r){ l++, r++; // queries are 0 index based if(l>r) return 0; return till(r)-till(l-1); } void remove(int x){ x++; while(x<=n){ tr[x] -= 1; x += lsb(x); } return; } }; long long count_swaps(std::vector<int> s) { int n = s.size(); vii pos((n*5)+100); int adjust = ((n*5)+100)/2; ll ans = 0; for(int i = 0; i < n; i++){ pos[adjust+s[i]].push_back(i); } vector<int> ptr(n*5+100, 0); BIT tr(n); for(int i = 0; i < n; i++){ if(tr.ask(i, i)==0) continue; int key = adjust-s[i]; int p = ptr[key]; while(pos[key][p]<=i) p++; while(tr.ask(pos[key][p], pos[key][p])==0) p++; ans += tr.ask(i+1, pos[key][p]-1); if(s[i]>0) ans ++; tr.remove(pos[key][p]); tr.remove(i); ptr[key] = p+1; } return ans; }
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