제출 #1278145

#제출 시각아이디문제언어결과실행 시간메모리
1278145nanaseyuzukiLet's Win the Election (JOI22_ho_t3)C++20
5 / 100
708 ms994644 KiB
#include <bits/stdc++.h> // Author: Kazuki_Will_Win_VOI_8703 #define fi first #define se second #define pii pair<int, int> #define ll long long using namespace std; const int mn = 5e2 + 5, lg2 = 20, mbit = (1 << 20) + 1, mm = 5e3 + 5; const double INF = 1e100; int n, K; struct Megumi{ int a, b; bool operator<(const Megumi& other) const{ if(b == -1 && other.b != -1) return true; if(b != -1 && other.b == -1) return false; if(b == other.b) return a < other.a; return b < other.b; } } e[mn]; double dp[mn][mn][mn]; void solve(){ cin >> n >> K; for(int i = 1; i <= n; i++){ cin >> e[i].a >> e[i].b; } sort(e + 1, e + n + 1); for(int i = 0; i <= n; i++){ for(int j = 0; j <= K; j++){ for(int k = 0; k <= K; k++){ dp[i][j][k] = INF; } } } dp[0][1][0] = 0; double ans = INF; for(int i = 1; i <= n; i++){ for(int j = 1; j <= K; j++){ for(int k = 0; k <= K; k++){ dp[i][j][k] = dp[i - 1][j][k]; if(k >= 1) dp[i][j][k] = min(dp[i][j][k], dp[i - 1][j][k - 1] + (double)e[i].a / (double)j); if(e[i].b != -1 && j >= 2 && k >= 1) dp[i][j][k] = min(dp[i - 1][j - 1][k - 1] + (double)e[i].b / (double)(j - 1), dp[i][j][k]); if(k == K) ans = min(ans, dp[i][j][k]); } } } cout << setprecision(15) << fixed << ans << '\n'; } signed main(){ ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int t = 1; // cin >> t; while(t--){ solve(); } }
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