| # | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
|---|---|---|---|---|---|---|---|
| 1277057 | al95ireyiz | 순열 (APIO22_perm) | C++20 | 0 ms | 0 KiB |
#pragma GCC optimize("O3", "fast-math", "unroll-loops", "no-stack-protector")
#include <bits/stdc++.h>
using namespace std;
#if !defined(ONLINE_JUDGE) and !defined(EVAL)
#include "template/debug.h"
#else
#define d(x...)
#endif
#define fr first
#define er erase
#define in insert
#define sc second
#define ll long long
#define pb push_back
#define vll vector<ll>
#define pll pair<ll,ll>
#define len(x) (ll) x.size()
#define all(x) x.begin(),x.end()
const ll INF = 1e9, INFL = 1e18;
const ll MOD = 1e9 + 7;
// const ll MOD = 998244353;
const ll maxn = 2e5 + 5;
ll n, m, k = 0;
ll f(ll ind, vector<int> &v){
// [0, ind - 1] kohne yol
// [ind, n - 1] yeni yol
ll cv = 0;
for(ll i = 0; i <= ind - 1; i ++){
cv += v[i];
}
for(ll i = ind; i <= n - 1; i ++){
if(i == ind) cv += v[i];
else cv += v[i] - (v[ind] - 1);
}
return cv;
}
std::vector<int> construct_permutation(long long _k)
{
m = _k;
vector<int> v, cv;
ll cm = 0, noilk = 0;
while(m){
ll l = 1, r = 60, cv;
while(l <= r){
ll md = (l + r) >> 1;
if((1LL << md) - noilk <= m){
cv = md, l = md + 1;
}
else{
r = md - 1;
}
}
v.pb(cv);
m -= (1LL << cv) - noilk;
if(noilk == 0) noilk = 1;
cm += cv;
}
n = len(v);
sort(all(v));
ll mn = INF, ind = 0;
for(ll i = 0; i < len(v); i ++){
ll x = f(i, v);
if(x < mn){
mn = x;
ind = i;
}
}
for(ll i = 0; i <= ind - 1; i ++){
for(ll j = cm - v[i] + 1; j <= cm; j ++){
// cout << j << ' ';
cv.pb(j - 1);
}
cm -= v[i];
}
for(ll i = ind + 1; i <= n - 1; i ++){
v[i] -= v[ind] - 1;
}
for(ll i = 1; i <= v[ind]; i ++){
cv.pb(i - 1);
}
for(ll i = ind + 1; i <= n - 1; i ++){
for(ll j = cm - v[i] + 1; j <= cm; j ++){
cv.pb(j - 1);
}
cm -= v[i];
}
return cv;
}
void _() {
ll q;
cin >> q;
auto v = construct_permutation(q);
for(auto i : v) cout << i << ' ' ;
}
signed main() {
ll tm = clock();
cin.tie(0)->sync_with_stdio(0);
ll t = 1;
// cin >> t;
for(ll tt = 1; tt <= t; tt ++) _();
cerr << "\n\033[1;31mTime: \033[1;30m" \
<< (double)(clock()-tm)/1000000 << "\033[1;32m seconds\n";
}