제출 #1275553

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1275553		afonsopereira	Aliens (IOI16_aliens)	C++20	4 / 100	1 ms	348 KiB

aliens

#include "aliens.h"
#include <vector>
#include <algorithm>
#include <deque>
using namespace std;

typedef long long ll;

// represents a linear function for convex hull trick
class linearfunction {
private:
    ll slope, intercept;
    
public:
    linearfunction(ll m, ll c) : slope(m), intercept(c) {}
    
    ll evaluate(ll x) const {
        return slope * x + intercept;
    }
    
    ll getslope() const { return slope; }
    ll getintercept() const { return intercept; }
};

// convex hull trick for maintaining minimum of linear functions
class convexhulltrick {
private:
    deque<linearfunction> hull;
    
    // check if middle line is redundant given left and right
    bool isredundant(const linearfunction& left, const linearfunction& mid, const linearfunction& right) {
        // using 128-bit integers to avoid overflow
        __int128 lhs = (__int128)(left.getslope() - right.getslope()) * 
                       (__int128)(mid.getintercept() - left.getintercept());
        __int128 rhs = (__int128)(left.getslope() - mid.getslope()) * 
                       (__int128)(right.getintercept() - left.getintercept());
        return lhs <= rhs;
    }
    
public:
    void insert(linearfunction func) {
        // handle duplicate slopes
        if (!hull.empty() && hull.front().getslope() == func.getslope()) {
            if (hull.front().getintercept() <= func.getintercept()) {
                return;
            }
            hull.pop_front();
        }
        
        // maintain convex hull property
        while (hull.size() >= 2) {
            if (isredundant(func, hull[0], hull[1])) {
                hull.pop_front();
            } else {
                break;
            }
        }
        
        hull.push_front(func);
    }
    
    ll querymin(ll x) {
        // remove suboptimal functions from the back
        while (hull.size() >= 2) {
            int lastidx = hull.size() - 1;
            if (hull[lastidx].evaluate(x) >= hull[lastidx - 1].evaluate(x)) {
                hull.pop_back();
            } else {
                break;
            }
        }
        
        return hull.back().evaluate(x);
    }
};

// segment representing a photo area
struct segment {
    int start, end;
    
    segment(int s, int e) : start(s), end(e) {}
    
    bool operator<(const segment& other) const {
        if (start != other.start) return start < other.start;
        return end > other.end; // prefer longer segments for same start
    }
    
    ll coverage() const {
        return (ll)(end - start + 1) * (end - start + 1);
    }
};

// preprocess points to get minimal set of segments
vector<segment> preprocesssegments(int n, vector<int>& r, vector<int>& c) {
    vector<segment> segments;
    segments.reserve(n);
    
    for (int i = 0; i < n; i++) {
        int startpos = min(r[i], c[i]);
        int endpos = max(r[i], c[i]);
        segments.emplace_back(startpos, endpos);
    }
    
    sort(segments.begin(), segments.end());
    
    // remove dominated segments
    vector<segment> filtered;
    int maxend = -1;
    
    for (const auto& seg : segments) {
        if (seg.end > maxend) {
            filtered.push_back(seg);
            maxend = seg.end;
        }
    }
    
    return filtered;
}

// calculate overlap between consecutive segments
ll calculateoverlap(const segment& prev, const segment& curr) {
    if (curr.start > prev.end) return 0;
    ll overlap = prev.end - curr.start + 1;
    return overlap * overlap;
}

// dp with lagrangian relaxation - returns (cost, count)
pair<ll, int> solvewithpenalty(const vector<segment>& segments, ll penalty) {
    int n = segments.size();
    vector<ll> dp(n + 1, 1e18);
    vector<int> cnt(n + 1, 0);
    
    dp[0] = 0;
    cnt[0] = 0;
    convexhulltrick cht;
    
    for (int i = 0; i <= n; i++) {
        if (i > 0) {
            ll x = segments[i - 1].end;
            ll mincost = cht.querymin(x);
            dp[i] = mincost + x * x + penalty;
            
            // find which transition gave us this value
            for (int j = 0; j < i; j++) {
                ll slope = -2 * segments[j].start + 2;
                ll overlap = (j > 0) ? calculateoverlap(segments[j - 1], segments[j]) : 0;
                ll base = segments[j].start - 1;
                ll intercept = dp[j] + base * base - overlap;
                ll transitioncost = slope * x + intercept + x * x + penalty;
                
                if (abs(transitioncost - dp[i]) < 1e-9) {
                    cnt[i] = cnt[j] + 1;
                    break;
                }
            }
        }
        
        if (i < n) {
            ll slope = -2 * segments[i].start + 2;
            ll overlap = (i > 0) ? calculateoverlap(segments[i - 1], segments[i]) : 0;
            ll base = segments[i].start - 1;
            ll intercept = dp[i] + base * base - overlap;
            
            cht.insert(linearfunction(slope, intercept));
        }
    }
    
    return {dp[n] - penalty * cnt[n], cnt[n]};
}

long long take_photos(int n, int m, int k, vector<int> r, vector<int> c) {
    auto segments = preprocesssegments(n, r, c);
    n = segments.size();
    
    if (n <= k) {
        // can use one segment per point
        ll total = 0;
        for (int i = 0; i < n; i++) {
            total += segments[i].coverage();
            if (i > 0) {
                total -= calculateoverlap(segments[i - 1], segments[i]);
            }
        }
        return total;
    }
    
    // binary search on penalty using ternary search optimization
    ll left = 0, right = (ll)m * m;
    
    while (right - left > 2) {
        ll mid1 = left + (right - left) / 3;
        ll mid2 = right - (right - left) / 3;
        
        auto [cost1, cnt1] = solvewithpenalty(segments, mid1);
        auto [cost2, cnt2] = solvewithpenalty(segments, mid2);
        
        ll adjusted1 = cost1 + mid1 * cnt1;
        ll adjusted2 = cost2 + mid2 * cnt2;
        
        if (adjusted1 > adjusted2) {
            left = mid1;
        } else {
            right = mid2;
        }
    }
    
    // check remaining candidates
    ll result = 1e18;
    for (ll penalty = left; penalty <= right; penalty++) {
        auto [cost, numsegments] = solvewithpenalty(segments, penalty);
        if (numsegments <= k) {
            result = min(result, cost);
        }
    }
    
    return result;
}

컴파일 시 표준 에러 (stderr) 메시지

aliens.h:1:9: warning: #pragma once in main file
    1 | #pragma once
      |         ^~~~
aliens_c.h:1:9: warning: #pragma once in main file
    1 | #pragma once
      |         ^~~~

• Subtask 1: 4 / 4
• Subtask 2: 0 / 12
• Subtask 3: 0 / 9
• Subtask 4: 0 / 16
• Subtask 5: 0 / 19
• Subtask 6: 0 / 40